How to calculate the bending radius of steel pipe

1. (1) Circumference = 2 π R (2 * circumference * radius)
(2) circle area= π r² Circumference * radius
(3) diameter = 2R (diameter is twice radius)

2. No illustrations, I'll tell you. The circumferential force and radial force of a pair of meshing gears act on the meshing point of the tooth profile of the pitch circle through the central line of the two wheels. The circumferential force coincides with the common tangent of the two pitch circles at the meshing point of the tooth profile of the pitch circle. The radial force passes through the meshing point of the tooth profile, coincides with the line connecting the center of the two pitch circles, points to the center of the pitch circle, and is perpendicular to the circumferential force. The circumferential force ft = 2t1 / D1; Radial force fr = ft * Tan α; among α- Pressure angle (20 in standard gears °， T1 - the torque on the pinion, D1 - the pitch diameter of the pinion (in the standard gear, the diameter of the dividing circle)< br />t1=9.55 × 10 ^ 6 (P1 / N1).
unit n * mm. P1 - power on pinion (kw), N1 - speed of pinion (R / min).

3.

Circular force: ft = 2T / d

Radial Force: FR = ft * Tan a

normal force: FN = ft / cos a
t-torque transmitted by pinion, unit: n.mm
d-pitch circle diameter of pinion, for standard gear, it is indexing circle diameter, unit: mm
a-meshing angle, for standard gear, a = 20 degrees, The forces of the big gear (driven gear) are equal, but the direction is opposite.

extended data:

Properties of the circumferential force:

1. In any case, the resultant force of the moment center is zero (that is, the moment center is a fixed point, which should have the conditions to balance the circumferential force)

The circular force can be divided into several parts or couples without changing the effect on the figure

The translation theorem is not suitable for circular force

Radial Force: generally refers to the force on a cylindrical object, the direction of which passes through the center of the cross section of the object and is perpendicular to the axis of the object, or the force on a spherical object passing through the center of the ball, which is called radial force. In short, it is the force acting on the diameter direction

4. The pressure P1 of the oil pressure port is large, and the radial force F1 of the oil on the gear shaft can be simply understood as the proct of the pressure P1 and the area A1 of the oil pressure port, that is, F1 = P1 * A1; On the other side (oil suction side), the pressure P2 is lower, and the radial force F2 = P2 * A2 on the gear shaft is smaller
A1 * P1 & gt; A2 * P2, which causes the radial force of the oil on the gear shaft.

5. No illustrations, I'll tell you. The circumferential force and radial force of a pair of meshing gears act on the meshing point of the tooth profile of the pitch circle through the central line of the two wheels. The circumferential force coincides with the common tangent of the two pitch circles at the meshing point of the tooth profile of the pitch circle. The radial force passes through the meshing point of the tooth profile, coincides with the line connecting the center of the two pitch circles, points to the center of the pitch circle, and is perpendicular to the circumferential force. Circular force ft = 2t1 / D1; Radial force fr = ft * Tan α; among α- Pressure angle (20 in standard gears °， T1 - the torque on the pinion, D1 - the pitch diameter of the pinion (in the standard gear, the diameter of the dividing circle)< br />T1=9.55 × 10 ^ 6 (P1 / N1). Unit: n * mm. P1 - power on pinion (kw), N1 - speed of pinion (R / min).

6. In general, spur gears do not proce axial force. Helical gear, bevel gear, worm gear transmission, will proce axial force
the axial force is the force in the direction of the axis (length), and the radial force is perpendicular to the axis and points to the axis (Center)
axial force cannot be "transmitted". The number of words is limited.

7. Fa Ft Fr

8. The radial force makes the shaft bend, the radial force increases the friction between the shaft and the bearing, the resistance increases and the efficiency decreases.

9. In gear transmission, if the tooth surface friction is not considered, the direction of the force is fixed, that is, along the meshing line, that is, the direction of the internal common tangent of the two gear base circles; If the transmitted torque is also constant, the force will not change. This is one of the advantages of involute gear transmission
if the tooth surface friction is considered, the situation is more complicated. In gear transmission, the tooth surface is rolling and sliding, and it is pure rolling at the node. Taking the node as the boundary, the sliding direction of the tooth profile is opposite. Therefore, the "state" of tooth surface friction is very complicated.

10. The forces borne by the gearbox need to be paid attention to:
1. The influence of the torque of the last stage (output stage) on the gearbox
2. If the gear is a helical gear, the axial component of the last stage needs to be considered. After selecting a pair of tapered roller bearings or a pair of angular contact bearings, whether the strength of the gearbox can withstand the axial component
3. The vibration impact force of the mechanism
4 There is no specific formula for the calculation of the above forces. The box can be regarded as a "plate" or a "rod" and calculated according to the general mechanical principles