The friction of a circle is the speed
friction torque: l = ∫ RDF = ∫ R* μ( mg/ π R^2)*2 π rdr=2 μ Mgr / 3
moment of inertia: J = Mr ^ 2 / 2
angular acceleration: β= L/J=4 μ G / 3R
uniform angular acceleration formula: ω 39;^ 2- ω^ 2=2 βΔθ, among ω 39;= 0
so the angular displacement of the disk Δθ= 3R ω^ 2/(8 μ g)
friction f= μ N
μ Is the friction coefficient
n is the positive pressure
so the friction is related to the friction coefficient and the mutual pressure of the two friction plates
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(1) when the spring has extended, there are more cases< br />F1=m* ω^ 2*r(F2=0)
F1+F2=m* ω^ 2 * r (when F2 points to the center of the circle, the rotating speed of the turntable is larger)
F1-F2 = m* ω^ (2) when the spring is compressed, the direction of F2 always points to the center of the circle. At this time, when the rotation speed of the object is large and the object is about to slide, F2 is the maximum static friction
in addition, when the spring is extended and the rotation speed of the object is large, the direction of F2 is also "pointing to the center of the circle". When the object is about to slide, F2 is also the maximum static friction
(3) for example, when the spring is originally extended, the turntable is stationary. The direction of static friction is first "inward" and then "outward"
before the object slides, the inward static friction decreases with the increase of rotation speed, and the outward static friction increases with the increase of rotation speed
(4) "replace spring with rope", rope will not give "repulsive force"
objects are not subject to "static friction" because they have no tendency to move
in fact, the force given by the spring is determined by the "shape variable" (elongation or compression), and the force on the rope can be changed Change with speed)
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