How to calculate the oblique force

1. Firstly, the forces and diagonal forces on the object are decomposed along the horizontal and vertical directions, and then solved by using the formula that the state of the object (equilibrium or acceleration state) follows (resultant force is 0 or F = MA).

2. Draw the angle between gravity, inclined elastic force, the opposite direction of elastic force and gravity θ So, the elasticity is equal to g × cos θ

3. G. N, f pull three force balance
establish the coordinate axis along the direction of N and f pull and decompose g
obviously
n = g * cosa
F pull = g * Sina
A is the slope angle of the inclined plane

4. When I came to see it, there was no answer. When I submitted it, I didn't know if anyone was ahead of my younger brother

I'd like to know your current identity: junior high school? Because this kind of problem is really simple

1. The resultant force of friction and supporting force is exactly the same as that of gravity: collinear + reverse + magnitude

2. As long as you think the friction can be large enough (actually impossible), unless 90 °， Otherwise, the balance of the three forces can be achieved

3. There must be something wrong with your stress analysis. Gravity is vertical and downward; The supporting force is perpendicular to the inclined plane and points from the inclined plane to the center of mass of the object; The friction is parallel to the inclined plane and upward

4. The component of gravity along the slope is GSIN θ， The component of gravity perpendicular to the slope is GCOS θ You're wrong

5. Equilibrium is vector, not scalar F + F = GCOS θ+ Gsin θ

equilibrium along an inclined plane: component of gravity GSIN θ， Friction GSIN θ Equilibrium perpendicular to the inclined plane: component of gravity GCOS θ， Support GCOS θ In the opposite direction)

for reference only. Used to be anonymous.

5. The condition of this question is not complete: what is the purpose of the thrust required by the iron plate? Is the iron plate still or moving? In order to move the iron plate, it is necessary to know the friction between the iron plate and the supporting surface, i.e. static friction or dynamic friction, in order to calculate the thrust required to push or maintain the movement.

6. All the forces must be decomposed on the slope, and then the algebraic sum must be calculated

7. Hello, I'm glad to be able to answer your question:

first of all, the friction and the downward component of the inclined plane are considered. The component of the friction perpendicular to the inclined plane is solved by orthogonal decomposition, and then the friction is calculated. The downward component of the inclined plane minus the friction is used to get the tensile force

this is the way of thinking. Anyway, we need to decompose the force and analyze the specific problems

I hope my answer will help you, thank you

8. 1. When the friction coefficient is known, the normal pressure on the inclined plane is calculated first, and the friction is calculated through the friction formula
2. When the uniform linear motion is achieved, the friction is calculated through the force balance along the inclined plane
3. When the uniform acceleration linear motion is known, the resultant force along the inclined plane is calculated by Newton's theorem, and then the friction is calculated according to the force along the inclined plane

9. 1. The slider receives gravity (i.e. universal gravitation), static friction F of inclined plane, supporting force F of inclined plane and air resistance are ignored
2. The direction of gravity is perpendicular to the direction of motion and does not do work, but can be calculated from gravity according to the balance of force: F = mg * sin37 °= 30N F=mg*cos37 °= 40N The work done is the distance of motion * the force in the direction of motion: w (f) = s * f * cos37 °= 2*2*30*0.8=96J WF=-S*F*sin37 °=- 96j, the negative sign is because the force is opposite to the direction of motion; Total work = the sum of the two equals 0

10. The work done by the force is equal to the force multiplied by the displacement (displacement in the direction of the force). The work done by the inclined plane is the work done by the friction. The work done by the friction is equal to the friction multiplied by the length of the inclined plane. Let the angle between the inclined plane and the horizontal plane be a, the length of the inclined plane be 3 / Sina, and the work be (3 / Sina) F. f is the friction.