How to calculate the impact of heavy objects
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Calculation formula: ft = {MV
F is the average force, t is the time, M is the mass of the object, V is the velocity, and} is the variation; This formula is understood as that the impact force and its time acting on the object are equal to the change of momentum of the object
F Δ t=m Δ V is a vector. When applying the momentum theorem, we should follow the parallelogram table rule of vector operation, or we can use the orthogonal decomposition method to transform vector operation into scalar operation. Suppose that FX (or FY) is used to represent the component of the combined force on the X (or y) axis Or) and VX (or vy) represent the components of the initial velocity and final velocity of the object on the X (or y) axis, then
IX = mvx-mvx & # 8320
Iy=mvy－mvy₀
The above two formulas show that the component of the impulse of the combined force on a certain coordinate axis is equal to the component of the increment of the momentum of the object on the same coordinate axis. When we write the component equation of the momentum theorem, for the known quantity, the positive value is taken for those in the same direction as the positive direction of the coordinate axis, and the negative value is taken for those in the opposite directionfor unknown variables, it is generally assumed that the direction is positive, if the calculation result is positive. It indicates that the actual direction is consistent with the positive direction of the coordinate axis. If the calculation result is negative, it indicates that the actual direction is opposite to the positive direction of the coordinate axis
extended data
when two objects collide with each other, the momentum of one object increases and that of the other decreases. In volleyball spiking, the quality of the ball is constant. If the object [hand] used to collide is to make volleyball move fast, the quality is to be large. It requires not only the hand to participate, but also the arm and trunk to participate, and the hand, arm and trunk to coordinate to form an overall force to increase the hitting quality. In this way, the hitting time is very short, but the impact is very strong
the force that occurs when objects collide with each other. In the process of collision or strike, the force between objects first increases suddenly and then disappears rapidly, also known as impulse or collision force. The characteristic of the impact force is that the action time is very short, but the magnitude can be very large
in sports activities, such as baseball batting, table tennis batting, volleyball spiking, football kicking, etc., all belong to collision, and running and pedaling can also be regarded as foot and ground collision. Because the collision interaction time is very short, often only a few hundredths of a second or even a thousandth of a second, the momentum changes greatly in this very short time, so it is subject to a great impact force
P = MV
I = ft = △ P
F can be calculated.
for example, when a bullet hits a wall at a speed of 400m / s, it takes 0.1s
P = 400m
F = P / T = 4000N
the momentum change of the object is Δ P = m (U-V), then the impulse is I = m (U-V), so the impulse is f = m (U-V) / T
where f, u and V are vectors.
first, the free falling time of 100 mm height:
t = (2 h / g) ^ 1 / 2
Second, the free falling speed of 100 mm height:
V = GT
third, the maximum bearing capacity of the test object at the moment = the weight of the weight of the code 25 kg * the free falling speed of 100 mm height / the impact time of the test object
we can first calculate the impact of the electric vehicle when it is added to people, and then divide the impact by the impact time to get the force
landing needs to be calculated by momentum
ft = MV
impact force F = 57 * √ 20 / T
t is not given in this question, so the condition is insufficient Here t refers to the time when the collision moves to rest, not the time when it falls
the - 57n upstairs is obviously unreasonable. The 57kg object is still on the ground, and the force is more than that. You can think of a 57kg sandbag as a person, with almost the same weight. If this person jumps to a scale, it doesn't need 1m. It's estimated that if he jumps 10cm, he will find that the pointer of the scale will reach a large value quickly
hope to solve your problem.
50kg object falling 3000m speed is about 245m / S (g = 10m / S2), if the impact time is 0.5 seconds, then use the formula: MV = ft to get f = 24500n.