How to calculate the concentrated force and bending moment at th
mid span load
superposition method: first, consider the bending moment of the left p to the mid span, because there is no given bearing number, I temporarily call the left bearing RA, and the right bearing RB
(1) first calculate the bearing reaction RA = P (2 / 3L) 178 1+2/3)/L² RB=P1/3L² 1+1/3)/L² Then Ma = - P (L / 3) (2L / 3) 178 can be obtained/ L² MB=-P(L/3)²( 2L/3)/L² < (2) calculate the left p-to-mid-span bending moment M1 = ma + ral / 2-P (L / 2-L / 3)
(3) also calculate the right p-to-mid-span bending moment M2
(4) add M1 + m2, then M = M1 + M2 = PL / 9
this is the idea, the process is too complex, I will not repeat it here
statics manual gives a formula for calculating the bending moment of two symmetrical point loads consolidated at both ends
m = PA & # 178/ L A is the distance from the point load to the fixed end, which is L / 3
I hope it is helpful for you
Bending moment = (F + L) * 2 / M
where 4T should be understood as the total weight, then the uniformly distributed load q = 40 / L. users need to understand whether the two ends of the beam are simply supported on the column or fixed on the concrete column
If 4T is the total weight and the two ends of the beam are simply supported on the column, the maximum bending moment is at the midspan section. The calculation formula of bending moment M on this section is as follows: M = 1 / 8 · QL & # 178; Where l is the calculation span = 1.05 × The clear span is 3.5 = 3.675 (m), so q = 40 / 3.675 = 10.88kn/m
∴M=1/8·qL² = zero point one two five × ten point eight eight × 3.675²= 18.37KN·m
if the beam is embedded in the column, calculate the fixed support, and the maximum bending moment is at the support; if the beam is only built on the column, then it should be simply supported, and the maximum bending moment is in the middle of the span. Check the structural static calculation manual
extended data:
precautions:
1. The bending moment at the fixed end is different from that mentioned above. If the two ends of a beam are fixed and subjected to uniform load, the bending moment at the middle of the span is smaller than that at the fixed end. Generally, the fixed end bending moment is larger, but it also depends on the situation
The bending moment at the fixed end is the bending moment at the fixed end, but the bending moment is different from that mentioned above. If the two ends of a beam are fixed and subjected to uniform load, the bending moment at the middle of the span is smaller than that at the fixed end Generally, the fixed end bending moment is larger, but it also depends on the situation. The resultant moment of the normal distribution of internal force component on the cross section is called bending moment4. The bending moment at the bottom of the beam is positive, and the bending moment at the top of the beam or the beam surface is negative. The positive sign of the bending moment of the column section is determined by the direction around the centroid, which is positive clockwise and negative anticlockwise. Fixed end bending moment belongs to bending moment, which is because it is constrained by one or more fixed joints
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< br > < look at the back two ZP is the Hong Kong Version, ch is the Bank of China, ll is the American version, J Japan, KH, Korea, etc.. A is the official version
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[the fourth year, F and G are in the first and second half of 2011, h and j are in the first and second half of 2012, K is in the first half of 2013
[the fifth two are the proction week (the week of proction in a year)
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