How to calculate the impact of falling objects

1. Let the velocity v = (2GH) ^ 1 / 2 of an object with mass n fall freely from high h, and the velocity decreases to 0 after time T
the orientation is positive
(f-mg) t = 0 - (- MV)
F = Mg + m (2GH) ^ 1 / 2 / T
impact force F = Mg + m (2GH) ^ 1 / 2 / T

2. It should know the impact time
50kg object falling 3000m speed is about 245m / S (g = 10m / S2), if the impact time is 0.5 seconds, then use the formula: MV = ft to get f = 24500n.

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4. If the air resistance is neglected, the energy conservation is MGH = (1 / 2) MV & # 178;, The final velocity V of the object is obtained, and then the impulse theorem is used to get ft = Δ MV, where t is the contact time between the object and the ground. It can be seen that the longer the time is, the smaller the force is. This is also the reason why the elastic object can buffer.

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6. Solution: set the height of a kilogram of things falling from the air to be h meters. From the formula of free falling body:
∵ H = 1 / 2xgt & # 178, M = 1 kg = 0.5kg
t = √ 2H / g
and VT = GT = g √ 2H / g
F = MVT
= MXG √ 2H / g
= 0.5x9.8kgm/s; √0.2041H
=4.6kgm/s² X0.4518√H·s²
= 2.078 √ H (Newton)
note: the impact force is proportional to the height change of H, and the greater the H is, the greater the impact force is
A: the impact force of a kilogram of things falling from high altitude is 2.078 √ hnon.

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9. Enough
3800x power consumption is less than expected
650W, even can double super point frequency

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