How to calculate the spring force on the cylinder

1.

Bottom area of cylinder inner diameter × System pressure = output force ----- n

for example: bore 40, system pressure 0.5MPa

20 × twenty ×π× 0.5 = 628n

thrust F1 on cylinder piston rod= π/ four × D2 × P ×&# 223; N)

tension on cylinder piston rod F2= π/ four × D2-d2 × P ×&# 223; N)

F1: push force when piston rod is pushed out

F2: pull force when piston rod is pulled back

D: inner diameter of cylinder pipe (piston diameter)

D: diameter of piston rod

P: air source pressure

& Load rate (at slow speed)= About 65% fast time= For example,

air pressure 0.5MPa (5.0985811kg force / square centimeter (kgf / cm))

cylinder diameter 50mm (5cm)

cylinder cross section = 3.14x (5 / 2) ^ 2 = 19.63 (square centimeter)

therefore, The theoretical output under 0.5MPa = 5.0985811 * 19.63 = 100.085 (KGF) can also be directly referred to the following cylinder output table

but it is only the theoretical output. Actually, it will be very fast to look up the table according to the working conditions

2. The former formula does not consider the friction resistance F, while the latter one considers the friction resistance F. the latter one is more practical.

3. It's so simple. First of all, for the cylinder you selected, he will definitely provide the parameters of pushing and pulling force under how much pressure. If you can't calculate, I will give you a formula, f = PS = P * (PI) * r * r, the area of cylinder diameter for pushing out, the area of cylinder diameter for retracting minus the area of push rod. You can calculate the pushing and pulling force. As for pushing each other, I don't care if you don't interact with each other, you are just like a wall, and the forces on both sides are the same, How much on one side is how much on the other side. If one side is big and the other side is small, one side will definitely run. It's not whether it's one or not. It's interaction

4. Besides the spring size, the design data of pressure spring need to calculate the maximum load and displacement size; Spring constant: expressed by K, when the spring is compressed, the load (kgf / mm) for every 1 mm distance increase; Spring constant formula (unit: kgf / mm): k = (g) × ｄ４)／８ × Ｄｍ３ × NC) g = steel molus of wire rod: piano wire g = 8000; Stainless steel wire g = 7300; Phosphor bronze line g = 4500; Brass wire g = 3500d = wire diameter do = od = outer diameter Di = id = inner diameter DM = MD = middle diameter do DN = total number of turns NC = effective number of turns = n-2 spring constant calculation example: wire diameter = 2.0mm, outer diameter = 22mm, total number of turns = 5.5 turns, steel wire material = piano wire k = (G × ｄ４)／８ × Ｄｍ３ × Ｎｃ＝８０００ × ２４／８ × ２０３ × 5) = 0.571kgf/mm, the K value of tension spring is the same as that of pressure spring. The initial tension of tension spring: the initial tension is equal to the force required to pull apart the close springs and coils. The initial tension occurs after the spring is rolled and formed. In the proction of tension spring, e to the different steel wire material, wire diameter, spring index, static electricity, grease, heat treatment, electroplating and so on, the initial tension of each tension spring is uneven. Therefore, when installing the tension spring of various specifications, it should be pre pulled until the distance between the parallel coils is slightly separated. The force required is called the initial tension. Initial tension = P - (k) × F1) = maximum load - (spring constant) × Tensile length) torsion spring constant: expressed in K, when the spring is twisted, every increase of 1 ° Load of torsion angle (kgf / mm). Formula of spring constant (unit: kgf / mm): k = (E) × ｄ４)／１１６７ × Ｄｍ × ｐ × Ｎ × R) E = steel molus of wire: piano wire e = 21000, stainless steel wire e = 19400, phosphor bronze wire e = 11200, brass wire e = 11200d = wire diameter do = od = outer diameter Di = id = inner diameter DM = MD = pitch diameter do DN = total number of turns r = arm of force under load p = 3.1416

5. For the design data of pressure spring
besides the spring size, it is more necessary to calculate the load of maximum load and displacement size; Spring constant: expressed by K, when the spring is compressed, the load (kgf / mm) for every 1 mm distance increase; Spring constant formula (unit: kgf / mm): k = (g) × d4)／8 × Dm3 × NC)
G = steel molus of wire rod: piano wire g = 8000; Stainless steel wire g = 7300; Phosphor bronze line g = 4500; Brass wire g = 3500 d = wire diameter do = od = outer diameter Di = id = inner diameter DM = MD = pitch diameter do-d n = total number of turns NC = effective number of turns = n-2
calculation example of spring constant: wire diameter = 2.0 mm, outer diameter = 22 mm, total number of turns = 5.5, steel wire material = piano wire
k = (G × d4)／8 × Dm3 × Nc＝8000 × 24／8 × two hundred and three × 3．5＝0．571kgf／mm
K=(G × d4)／8 × Dm3 × Nc＝8000 × 0.84／8 × six point six three × 2) = 1.34kgf / mm
3276.8/4599.936 = 0.712358 preload 0.65
when fixed, the compression is 2mm
tension spring
the K value of tension spring is the same as that of pressure spring
initial tension of tension spring: the initial tension is equal to the force required to properly pull apart the close springs and coils, and the initial tension occurs after the springs are rolled and formed. In the proction of tension spring, e to the different steel wire material, wire diameter, spring index, static electricity, grease, heat treatment, electroplating and so on, the initial tension of each tension spring is uneven. Therefore, when installing the tension spring of various specifications, it should be pre pulled until the distance between the parallel coils is slightly separated. The force required is called the initial tension. Initial tension = P - (k) × F1) = maximum load - (spring constant) × Tensile length) torsion spring
spring constant: expressed as K, when the spring is twisted, every 1 increase in the value of ° Load of torsion angle (kgf / mm). Formula of spring constant (unit: kgf / mm): k = (E) × d4)／1167 × Dm × p × N × R)
e = steel molus of wire: piano wire e = 21000, stainless steel wire e = 19400, phosphor bronze wire e = 11200, brass wire e = 11200 d = wire diameter do = od = outer diameter Di = id = inner diameter DM = MD = pitch diameter do DN = total number of turns r = arm of force under load p = 3.1416.

6. Is there no coefficient of elasticity (k)? F＝k Δ l

7. Unknown_Error

8. F = 1 / 2kx, f is the size of the elastic force, unit Newton (n), K is the proportional coefficient (n / M), X is the spring variable, unit meter (m), pull the spring to the longest, measure out x can be found, hope to adopt

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