How to calculate the force of physical fall
the force analysis of the object should be done first. When the object moves at a constant speed, the external force on the object is zero. If the air friction is not taken into account, the resistance of general objects is the sliding friction with the ground. At this time, the sliding friction is equal to and opposite to other forces on the object. Then the forces in both directions add up to zero. So we're going to move at a constant speed for zero
the orientation is positive
(f-mg) t = 0 - (- MV)
F = Mg + m (2GH) ^ 1 / 2 / T
impact force F = Mg + m (2GH) ^ 1 / 2 / T
If an object with a mass of 1kg falls freely, an elastic collision occurs, and the collision time t is 0.01s
when an object falls from a height of 1m, the impact force to be calculated is 885.438n
the calculation process is as follows:
momentum conservation and impulse conservation
the falling velocity v = √ (2GH) = √ (2 × 9.8) ≈ 4.427 M / s
MV & # 39- MV=FT,F=MV'- MV ÷ T=1 × 4.427+1 × 4.427 ÷ 0.01 = 885.438 (Newton)
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extended data:
in an ideal case, after the collision, the deformation of the object can be recovered, there is no heat and sound, and there is no loss of kinetic energy. This kind of collision is called elastic collision, also known as fully elastic collision. True elastic collisions occur only between molecules, atoms, and even smaller particles. In daily life, when the hard wood ball or steel ball collides, the loss of kinetic energy is very small and can be ignored. Usually, their collision can also be regarded as elastic collision
According to Newton's theory, the complete elastic collision is one with coefficient of restitution. Please note that the latter is completely equivalent to the former, but it is easier to make a quantitative analysis of the problem by using the latterLaw of conservation of momentum:
M & # 8321; v₁+ m₂ v₂= m₁ v₁ 39;+ m₂ v₂ 39;
Law of conservation of energy:
(1 / 2) M & 8321; v₁ 178;+ 1/2m₂ v₂ 178;= 1/2m₁ v₁ 39; 178;+ 1/2m₂ v₂ 39; 178;
free fall is the motion of a conventional object with zero initial velocity only under the action of gravity, which is called free fall motion. Free falling body motion is an ideal physical model Free fall) is any object under the action of gravity, at least in the initial, only gravity as the only force under the condition of inertial trajectory, is the initial velocity of 0 uniform acceleration motion. Since this definition does not specify the direction of the initial velocity, it also applies to the initial upward movement of the object
In the case of free fall, gravity outside the atmosphere proces weightlessness, sometimes any weightlessness state is called free fall e to inertial motion. This may also apply to weightlessness because the body is far away from gravitation. Although the strict definition of technical application does not include the movement of objects subject to other resistance, such as air resistance, in non-technical use, will pass through the atmosphere without deployment of parachutes, or lifting devices, also often referred to as free fallresistance in this case, to prevent them from procing a completely weightless state, thus parachuting "free fall" after reaching the terminal speed to proce a sense of body weight is supported in an air cushion
the motion of free falling body originates from gravity. The motion of a body falling from a relatively static position under the action of gravity is called free falling body motion (its initial velocity is VO = 0 m / s). For example, it is a physical phenomenon that occurs when a hand holds an object without any external force
the law of free fall: v = GT, H = 0.5gt & # G acceleration of gravity, t falling time, H falling height, V is the velocity at time t)
if you have studied the momentum theorem, you know that there is mv-mv & #= FT
m is mass, V is 0, V is 39; For the velocity when touching the ground, mv-mv & # 39; F is the interaction between the object and the ground. Idealize it to a fixed value. T is time
if it's soft
trapped for a long time, the force is small
have you studied it with
momentum theorem
ft = MV
right? V is calculated by dynamic
formula
if the sinking time in the soil is 1s
MV = 60 * 100 *
radical number
two = f * 1-600 * 1
F = 600 + 6000 * radical number two
The calculation formula of instantaneous velocity of free falling body is v = GT; The calculation formula of displacement is
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extended data
when the object over the earth takes the center of the earth as the reference point to describe its motion, it moves around the earth in a uniform circular motion. The combined external force on the direction of connecting with the center of the earth is a centripetal force pointing to the center of the earth, which is caused by the gravitational force between the object and the earth, The gravitational action between two objects only depends on the structure and size of the object field
usually in the air, with the increase of the velocity of the free falling body, the resistance of the air to the falling body increases graally
when the gravity of the object is equal to the resistance it is subjected to, the falling body will fall at a constant speed, and the maximum speed it reaches at this time is called the terminal speed. For example, when parachutists jump from an aircraft, if they don't open an umbrella, their terminal speed is about 50 m / s, and when they open an umbrella, their terminal speed is about 6 m / s
G is the acceleration of gravity, G ≈ 9.8m / (s ^ 2)
(1) the law of velocity changing with time: v = GT
(2) the law of displacement changing with time: H = (1 / 2) GT ^ 2
(3) the variation of velocity with displacement: 2GS = V ^ 2if you have studied the theorem of momentum, you know that there is mv-mv & #= FT
m is the mass, V is 0, V is 39; For the velocity when touching the ground, mv-mv & # 39; For his momentum change. F is the interaction force between the object and the ground. Idealize it to a fixed value. T is time.