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BCN network computing power

Publish: 2021-05-13 09:18:10
1. 1. Walk about 190 meters from entrance / exit C of Shiqiao station to Baiyue Square Station (Shiqiao station) in Panyu, take Panyu No.23 bus B (no monthly ticket) (4 stops) to Panyu Hotel station, then transfer to No.310 bus (no monthly ticket) (19 stops) to central hub station (University town). Walk about 350 meters to Beiting Village (total mileage: 27600 meters); Time required: about 90 minutes * Note: for reference only, factors such as waiting, walking and traffic jam are not considered.)
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2. Take a taxi: 12.0km in total, the cost is 36.00 yuan. Note: the information is for reference only, and can not be used as the basis of payment. Toll and bridge toll are not included in the fee, Traffic jam and other factors may increase the cost significantly
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3. Take Metro Line 3 (Panyu Square Tianhe passenger station) (4 stops) from Shiqiao station to Lijiao station, then take bus No.35 (8 stops), no.565 (9 stops) from lunxiuchang station Take bus 86 (take 9 stops) and get off at the central hub station (University Town). Walk about 350 meters to Beiting village, Panyu (total mileage: 24900 meters; Time required: about 50 minutes * Note: for reference only, factors such as waiting for bus, walking and traffic jam are not considered.)
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4. Walk about 190 meters from entrance / exit C of Shiqiao station to Panyu Baiyue Square Station (Shiqiao station), take Panyu No.18 (no monthly ticket) (4 stops), 309 (4 stops) to Xinghai Park Station (Panyu), Go to Xinghai Park Station (Panyu) on the other side of the road and take bus 310 (monthly ticket is not supported) (take 20 stops) to the central hub station (University Town). Walk about 350 meters to Beiting Village (total mileage: 28000 meters); Time required: about 95 minutes * Note: for reference only, factors such as waiting, walking and traffic jam are not considered.)
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5. From entrance / exit C of Shiqiao station to Baiyue Square Station (Fuhua West Road), take Panyu No.7 (no monthly ticket) (2 stops) to fucheng station (Shichang Hotel Station), then take No.310 (no monthly ticket) (17 stops) to central hub station (University City). Walk about 350 meters to Beiting Village (total mileage: 25700 meters) Time required: about 80 minutes * Note: for reference only, factors such as waiting for bus, walking and traffic jam are not considered.)
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6. Walk about 320 meters from the entrance and exit of Shiqiao station a to danshanqiao station (Danshan station) in Panyu, take Panyu No.4 road a (no monthly ticket) (3 stops) to fucheng station (Shichang Hotel Station) in Panyu, Go to the fucheng station (Shichang Hotel Station) on the opposite side of the road and take bus 310 (monthly ticket is not supported) (take bus No.17) to the central hub station (University City). Walk about 350 meters to Beiting Village (total mileage: 25900 meters; bus No; Time required: about 85 minutes * Note: for reference only, factors such as waiting, walking and traffic jam are not considered.)
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7. Walk about 270 meters from entrance / exit C of Shiqiao station to Panyu Baiyue Square Station (Tingsha Village Station), take No.305 (no monthly ticket is supported) (take 1 station) to Beicheng Zhongba station (Panyu), Go to Panyu Hotel station which is located on another road (Dabei Road), transfer to 310 Road (monthly ticket is not supported) (take 19 stops) and get off at the central hub station (University Town). Walk about 350 meters to Panyu Beiting Village (total mileage: 26600 meters); Time required: about 85 minutes * Note: for reference only, factors such as waiting, walking and traffic jam are not considered.)
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8. Walk about 270 meters from entrance / exit C of Shiqiao station to Panyu Baiyue Square Station (Tingsha Village Station), sit on Zhongcun Panyu passenger dedicated line (monthly ticket is not supported) (2 stops) and get off at Xinghai Park Station (Panyu), Go to Xinghai Park Station (Panyu) on the opposite side of the road and take bus 310 (monthly ticket is not supported) (take 20 stops) to the central hub station (University Town). Walk about 350 meters to Beiting Village (total mileage: 27700 meters); Time required: about 90 minutes * Note: for reference only, factors such as waiting, walking and traffic jam are not considered.)
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9. Walk about 270 meters from entrance / exit C of Shiqiao station to Panyu Baiyue Square Station (tingshacun station), take Luoxi Shiqiao line (Shiguang Road) (monthly ticket is not supported) (1 station), 301 Road (Zhanqian road Shiqiao bus station) (1 station) to Panyu Shiqiao bus station, Go to Shiqiao bus station (Panyu) at another road (Dabei Road) and transfer to 310 bus (no monthly ticket) (take 18 bus stops) and get off at the central hub (University Town). Walk about 350 meters to Beiting Village (total mileage: 26000 meters); Time required: about 80 minutes * Note: for reference only, factors such as waiting for bus, walking and traffic jam are not considered.)
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2. This kind of injection, really say, treat the symptoms but not the root cause. If you really want to go, you'd better use the Chinese medicine!
3.

Solution:

conjecture ∠ BQM = 60 °

reason:

in Figure 1:

because △ ABC is an equilateral triangle

so AB = AC = BC, ∠ ABC = C = ACB = 60 °

because BM = CN

so △ ABM ≌ BCN (SAS)

so ≌ BAM = ≌ CBN

because ≌ BQM = ≌ ABQ + BAM

so ≌ BQM = ≌ ABQ + CBN = ≌ ABC

because ≌ ABC = 60 °

so ∠ BQM = 60 °

compared with figure 1, n is also between AC, and there is no difference.

in Figure 3, △ ABM ≌ △ BCN

so ∠ M = n

so ∠ BQM = n + NAQ = m + Mac

because ∠ m + MAC = ACB = 60 °

so ∠ BQM = 60 °

To sum up, BQM is always equal to 60 °

Wu Yunchao of Jiangsu Province wishes you progress in your study

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in a certain proportion, which can effectively promote the expansion and decomposition of stubborn fat layer, so that fat can be more easily decomposed into fatty acids instead of supplying body energy.
5. Prove: as shown in the figure, in △ ABC and △ DCB,
∫ AB = DC, AC = dB, BC = CB,
≌ ABC ≌ DCB
{MBC =} MCB,
} BM = cm (equiangular to equilateral)

∫ cn ‖ BD, BN ‖ AC,

{quadrilateral bmcn is parallelogram,
} quadrilateral bmcn is diamond,
{BN = CN.
} BCN =} CBN


hope to adopt
6. 1. AC = MC, NC = CB, angle MCB = angle ACN = 120 degrees, so triangle ACN is equal to triangle MCB
angle ANC = angle MBC, because angle ANC + angle NAC = 60 degrees, so angle NAC + angle MBC = 60 degrees, so in triangle AOB,
angle AOB = 120 degrees, that is, angle DOE = 120 degrees
2. It has been proved that triangle ACN is equal to triangle MCB. So an = MB
AC = MC, angle DAC = angle EMC (using the congruent triangle above), angle MCA = angle MCE = 60 degrees, so triangle ACD is equal to triangle MCE. So, ad = me. Combined with an = MB, so DN = EB
3. It has been proved that ACD of triangle is equal to MCE of triangle, so DC = EC and DCE = 60 degrees. Therefore, the triangle CDE is an equilateral triangle
4. Connect ed. Because the triangle CDE is an equilateral triangle. So, the angle Dec = 60 degrees, the angle ECB = 60 degrees, so De is parallel to ab.
7. ∠A ∠A ∠A A
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10. (1) Prove: connect BN
because quadrilateral ABCD is square
so angle BCN = angle DCN = 45 degrees
because CN = CN
so triangle BCN and triangle DCN are congruent (SAS)
so NB = nd
angle MBN = angle CDN
because BP's vertical bisector Mn intersects AC at point n
so angle BMN = angle PMN = 90 degrees
BM = MP = 1 / 2bp
NB = NP
so nd = NP
(2) prove: connect BN
because BP's vertical bisector Mn intersects AC at point n
so angle BMN = angle PMN = 90 degrees Extend BC so that CF = AE, Connect DF
because Quad ABCD is square
so angle BCN = angle DCN = 45 degrees
angle BCD = angle DAE = angle ADC = angle ADC = 90 degrees
ad = DC
because angle BCD + angle DCF = 180 degrees
so angle DCF = 90 degrees
so angle DAE = angle DCF = 90 degrees
so triangle AED and triangle CFD are all equal (SAS)
so angle ade = angle CDF
de = DF
because NB = NP (proven)
so angle MBN= Angle NPN
because angle MBN = angle CDN (proved)
so angle MPN = angle CDN
so p, C, D, N four points are concentric
so angle PDE = angle BCN = 45 degrees
because angle ADC = angle ade + angle PDE + angle CDP = 90 degrees
so angle CDP + angle CDF = angle PDF = 45 degrees
so angle PDE = angle PDF = 45 degrees
because PD = PD
so triangle PDE and triangle PDF congruence (SAS)
so EP = FP
because FP = CP + CF = CP + AP
so AP + CP = EP
(3) solution: because quadrilateral ABCD is square
so a B = BC = 2
angle ABC = 90 degrees
so triangle ABC is isosceles right triangle
according to Pythagorean theorem:
AC ^ 2 = AC ^ 2 + BC ^ 2
so AC = 2 times root 2
because P is the midpoint of BC
so CP = BP = 1 / 2BC = 1
because BM = MP = 1 / 2bp
so BM = 1 / 2
because angle CMP = 90 degrees (proved)
so angle ABC = angle CMP = 90 degrees
so MP parallel AB
so an / AC = BM / b C
so an = radical 2 / 2
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