What is the supporting force of the sea floor to an object

There is no specific formula for supporting force. Sometimes supporting force = gravity or = friction

when expounding the concept of supporting force, it is always said that one object has supporting force for another, then the latter is the stressed object, and the point of action should be marked on the stressed surface. For example, if a wooden block is placed on the horizontal desktop and is supported by the desktop, the point of action of the supporting force is marked on the center of gravity of the wooden block

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extended data:

I. nature of force:

1. Materiality: force is the effect of object (matter, mass) on object (matter, mass). When an object is under the action of force, another object must exert this effect on it. Force cannot exist independently without object

3. Vectoriality: force is a vector, which has both magnitude and direction

4. Simultaneity: the force proced and disappeared at the same time

2. According to the effect of force, it can be divided into tension, tension, pressure, supporting force, power, resistance, centripetal force, restoring force, etc< According to the research object, it can be divided into external force and internal force

4. According to the action mode of force, it can be divided into non-contact force (such as gravitational force, electromagnetic force, etc.) and contact force

5. Four basic interactions (forces): gravitational interaction, electromagnetic interaction, strong interaction and weak interaction

设物体重为G，体积为V，
将物体浸没在水中，弹簧测力计的示数：
F _示 =G-F _浮 ，则：
G-F _浮 =5N，
ρ _物 Vg-ρ _水 V _排 g=5N，
因为V _排 =V，
所以ρ _物 Vg-ρ _水 Vg=5N，------①
将物体放入装有酒精的容器，容器底部对物体的支持力：
F _支持力 =G-F _浮 ′，则：
G-F _浮 ′=6N，
ρ _物 Vg-ρ _酒精 V _排 g=6N，
因为V _排 =V，
所以ρ _物 Vg-ρ _酒精 Vg=6N，------②
②-①得：
ρ _水 Vg-ρ _酒精 Vg=1N，
1×10 ³ kg/m ³ -0.8×10 ³ kg/m ³ ×V×10N/kg=1N，
解得：
V=5×10 ^-4 m ³ ，
代入①得：
ρ _物 ×5×10 ^-4 m ³ ×10N/kg-1×10 ³ kg/m ³ ×5×10 ^-4 m ³ ×10N/kg=5N
解得：
ρ _物 =2×10 ³ kg/m ³ ．
答：物体的体积和密度分别为5×10 ^-4 m ³ 、2×10 ³ kg/m ³ ．

The pressure f < sub > n < / sub > ′ on the inclined plane is perpendicular to the downward direction of the inclined plane,
the supporting force F < sub > n < / sub > on the object is perpendicular to the upward direction of the inclined plane,
the two forces are equal, f < sub > n < / sub > ′ = f < sub > n < / sub >, the action points are on the contact surface of the object and the inclined plane,
from the action point of the force, Make a directed line segment along the direction of the force,
then make a schematic diagram of the pressure and supporting force; The schematic diagram of the force is as follows: