10m computing power

1. Illegal fund-raising refers to the behavior that an entity or indivial raises funds from the public by issuing stocks, bonds, lotteries, investment fund securities or other creditor's rights certificates without the approval of relevant departments in accordance with legal proceres, and promises to repay the principal and interest or give returns to the investors in currency, material object or other ways within a certain period of time
the crime of financial fraud refers to the act of defrauding public or private property or the credit of financial institutions and damaging the order of financial management by making up facts or concealing the truth for the purpose of illegal possession.

2. 1 mm water column = 10 Pa
10 m = 10 000 PA = 0.1 MPa
1 mm mercury column (mmHg) = 133.322 PA
1 project atmospheric pressure = 98.0665 kPa

3. Sometimes it is also called head loss
in fact, it is the pressure allowed to drop 10 meters of water column, which is about one kilogram of pressure
or 0.1 MPa
because of the hydraulic conditions of the pipeline itself
the water pressure will drop when the valve on the pipeline
elbow, etc.
that is, we often call the extended range water loss and local water loss

4. The bigger the diameter of the pipe, the smaller the diameter of the pipe. It won't affect the flow rate. It's just that the flow rate in the small pipe is faster
the steps to select the pipe according to your question
calculate the volume flow: (10 / 60) / (0.7 / 0.1) = 0.0238m3/s, and the nominal flow of the compressor is the flow of the standard state. When calculating the flow in the pipeline, it should be converted into the flow at the outlet of the compressor
determine the flow rate according to the pipe material. Here I give a more common 15m / s
pipeline cross-sectional area 0.0238/15 = 0.0015873m
pipeline diameter: R ^ 2 = 0.0015873 / pi = 5.053 * 10 ^ - 4m
R = 0.0225m
DN = 2 * 0.0225 = 0.045m = 45mm
it's usually DN50. Or G2
if important pipelines need to be checked. The stress of laminar flow on the pipe wall caused by friction should be considered in the check.

5. Sometimes it is also called head loss. In fact, it is the pressure allowed to drop 10 meters of water column, which is about one kilogram pressure or 0.1 MPa. Because of the hydraulic conditions of the pipeline itself, the water pressure will drop when the valves and elbows on the pipeline, which is often called extended water loss and local water loss

6. Functional relationship: w = 1|2mvv (M is the air mass, W is the work of air on the sail)
W = Pt
m = QV (V is the volume of wind, q is the air density)
V = VTS
so p = 1|2qsvv
F = PS = 1|2qssvv
note: This is an idealized model, assuming that the speed of air molecules after impacting the sail is reced to 0, and ignoring the speed of the sailboat

7. Add a parameter, air density< br />
http://..com/question/33315266.html?fr=qrl&cid=203&index=3&fr2=query
this is about how to calculate the wind pressure. The sail area is probably the thrust

What do you mean by power? The engine power algorithm is different.

8. 1. Flow = flow area X flow rate X time
2. Assuming that 10mm is the inner diameter of the pipe, flow = 3.1415x0.01x0.01/4 (M2) x10m / s, x3600s = 2.827m3

9. P = pGH = 1000 * 9.8 * 10 = 98000 (PA)
F = g water = m water, g = PVG = 1000 (6 * 6 * 10) * 9.8 = 3528000 (n)
calculate the pressure inside the liquid, remember P = pGH, there is no mistake with this formula
pressure is the gravity of the liquid
for easy understanding, you can dece the formula, the pressure of the liquid at a depth in a container is equal to gravity divided by contact area, Gravity is also equal to the contact area times the depth times the density, so after approximately dividing, it will be found that the internal pressure of the liquid is only related to the depth and density