How to calculate the force of inclined plane
I'd like to know your current identity: junior high school? Because this kind of problem is really simple
1. The resultant force of friction and supporting force is exactly the same as that of gravity: collinear + reverse + magnitude
2. As long as you think the friction can be large enough (actually impossible), unless 90 °, Otherwise, the balance of the three forces can be achieved
3. There must be something wrong with your stress analysis. Gravity is vertical and downward; The supporting force is perpendicular to the inclined plane and points from the inclined plane to the center of mass of the object; The friction is parallel to the inclined plane and upward
4. The component of gravity along the slope is GSIN θ, The component of gravity perpendicular to the slope is GCOS θ You're wrong
5. Equilibrium is vector, not scalar F + F = GCOS θ+ Gsin θ
equilibrium along an inclined plane: component of gravity GSIN θ, Friction GSIN θ Equilibrium perpendicular to the inclined plane: component of gravity GCOS θ, Support GCOS θ In the opposite direction)
for reference only. Used to be anonymous.
first of all, the friction and the downward component of the inclined plane are considered. The component of the friction perpendicular to the inclined plane is solved by orthogonal decomposition, and then the friction is calculated. The downward component of the inclined plane minus the friction is used to get the tensile force
this is the way of thinking. Anyway, we need to decompose the force and analyze the specific problems
I hope my answer will help you, thank you
The larger the inclination angle between the inclined plane and the plane, and the shorter the inclined plane, the smaller the labor saving, but the less the distance. Inclined plane is widely used in daily life, such as mountain road, conveying roller, inclined conveyor belt and so on
the mechanical efficiency of the inclined plane is 100% without calculating any resistance. If the friction is very small, the efficiency can be very high. That is to say, F2 is the force, s is the length of the inclined plane, h is the height of the inclined plane, and the weight of the object is g. When the useless resistance is not considered, according to the principle of work, it can be obtained that F2s = GH
if the slope of the inclined plane is smaller, that is, the angle between the inclined plane and the horizontal plane is smaller, the force applied to the object will be smaller, but the moving distance will be longer; vice versa. Assuming that the moving load does not cause energy storage or dissipation, the mechanical benefit of the slope is the ratio of its length to the lifting height
The friction between solid surfaces can be divided into sliding friction, rolling friction, static friction, rolling friction and rotational friction. In engineering technology, people use lubricating oil to rece frictionIf two rubbing surfaces are isolated by a layer of liquid, liquid friction can occur between them. If the liquid isolation is not complete, mixed friction may also occur
air track works by air friction. The working principle of lubricating oil and air track is to use "liquid or gas (i.e. fluid) friction to replace solid friction" to work
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, the pulling force F along the inclined plane and the normal reaction n of the inclined plane form a closed force triangle f = WSiN α Since f is the input force and W is the output force, the mechanical benefit of the inclined plane is w / F = 1 / sin α= s/h This is the slope principle: the ratio of the output force to the input force is equal to the ratio of the hypotenuse of the right triangle ABC to the right side
because s > H, the mechanical benefit of the slope is greater than 1. The slope conveyor belt in Panshan highway and material conveyor is the specific application of slope principle.
W = fscos α
F is the force acting on the object, s is the displacement of the object, α It is the angle between the positive direction of force F and displacement s
the work done by gravity on the inclined plane is the proct of the distance of the object moving along the direction of force and the force
the vertical force of the weight on the inclined plane = 900 × Cosa (downward)
horizontal force of heavy object on inclined plane = 900 × Sina (left)
horizontal force of thrust on inclined plane = 300 × Sina (right)
vertical force of thrust on inclined plane = 300 × Cosa (up)
so the pressure of the weight on the inclined plane (vertical force) = cosa (900 = 300) = 600cosa (n)

normal pressure of object to inclined plane = mgcos α
(without drawing, you can also imagine a special position: α= 0, positive pressure = mg, α= 90º Positive pressure = 0, so it's cos α, And sliding force = mgsin α On the contrary)
sliding friction f = n· μ= mgcos α·μ, The direction of force is opposite to that of motion.
