How to calculate the torque spring force

1.

Calculation of spring weight (kg):

wire diameter × Wire diameter × Total number of spring turns × Pitch diameter of spring × one point nine three seven ÷ 100000

elastic formula

F = KX, f is elastic force, K is stiffness coefficient (or obstinacy coefficient), and X is the length of spring lengthening (or shortening). Example 1: when a spring with a stiffness coefficient of 100N / M is pulled by 5N force, the spring will be lengthened by 5cm. Example 2: when a spring is pulled by 10N force, the total length is 7cm, and when it is pulled by 20n force, the total length is 9cm

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extended data:

structure classification

< P > according to the mechanical properties, springs can be divided into tension spring, compression spring, torsion spring and bending spring, according to the shape, they can be divided into disc spring, ring spring, plate spring, spiral spring, truncated cone scroll spring and torsion bar spring, According to the manufacturing process can be divided into cold coil spring and hot coil spring. Ordinary cylindrical spring is widely used because of its simple manufacture, various types and simple structure

Generally speaking, the manufacturing materials of spring should have high elastic limit, fatigue limit, impact toughness and good heat treatment performance, and the commonly used ones are carbon spring steel, alloy spring steel, stainless spring steel, copper alloy, nickel alloy and rubber. The manufacturing methods of spring include cold rolling and hot rolling. The diameter of spring wire less than 8 mm is generally cold rolled, and the diameter greater than 8 mm is hot rolled. Some springs need to be pressed or shot peened after being made, which can improve the bearing capacity of the spring

2. Besides the spring size, the design data of pressure spring need to calculate the maximum load and displacement size; Spring constant: expressed by K, when the spring is compressed, the load (kgf / mm) for every 1 mm distance increase; Spring constant formula (unit: kgf / mm): k = (g) × ｄ４)／８ × Ｄｍ３ × NC) g = steel molus of wire rod: piano wire g = 8000; Stainless steel wire g = 7300; Phosphor bronze line g = 4500; Brass wire g = 3500d = wire diameter do = od = outer diameter Di = id = inner diameter DM = MD = middle diameter do DN = total number of turns NC = effective number of turns = n-2 spring constant calculation example: wire diameter = 2.0mm, outer diameter = 22mm, total number of turns = 5.5 turns, steel wire material = piano wire k = (G × ｄ４)／８ × Ｄｍ３ × Ｎｃ＝８０００ × ２４／８ × ２０３ × 5) = 0.571kgf/mm, the K value of tension spring is the same as that of pressure spring. The initial tension of tension spring: the initial tension is equal to the force required to pull apart the close springs and coils. The initial tension occurs after the spring is rolled and formed. In the proction of tension spring, e to the different steel wire material, wire diameter, spring index, static electricity, grease, heat treatment, electroplating and so on, the initial tension of each tension spring is uneven. Therefore, when installing the tension spring of various specifications, it should be pre pulled until the distance between the parallel coils is slightly separated. The force required is called the initial tension. Initial tension = P - (k) × F1) = maximum load - (spring constant) × Tensile length) torsion spring constant: expressed in K, when the spring is twisted, every increase of 1 ° Load of torsion angle (kgf / mm). Formula of spring constant (unit: kgf / mm): k = (E) × ｄ４)／１１６７ × Ｄｍ × ｐ × Ｎ × R) E = steel molus of wire: piano wire e = 21000, stainless steel wire e = 19400, phosphor bronze wire e = 11200, brass wire e = 11200d = wire diameter do = od = outer diameter Di = id = inner diameter DM = MD = pitch diameter do DN = total number of turns r = arm of force under load p = 3.1416

3. With the development of armour and the emergence of fortification, the function of indivial bows and crossbows has been weakened accordingly. They can not penetrate the shield with bronze, and of course can not destroy the bunker made of bricks and stones. Although people have tried to make huge crossbows, the launching force proced by the elastic deformation of the crossbow arm is close to the limit, which can not give more power to the arrow stone or projectile. The catapult invented by the craftsmen of Dionysus first adopted the latest achievement of mechanical research - torsion spring, that is, using the torsion generated by two bundles of tensioned horsehair, leather rope or animal tendons as the power to drive the crossbow arm to drive the bowstring to shoot projectiles or arrows. The manufacture of catapult is a very precise work. Craftsmen distinguish the specifications of catapult according to the size of torsion spring, which in turn depends on the diameter of torsion spring. In practice, the Greeks summed up the classic sizes of catapult. Take the torsion spring component as an example, the baffle plate is made of a square board, and its thickness is equal to the diameter of torsion spring, The side length is equal to the length of the torsion spring. On the secondary basis, two parallel lines Ag and de are established according to half of the ratio. Then two arc lines Ag and de are established with three times of the diameter of the torsion spring as the radius. The shift of the torsion spring assembly is completed. The mortise and tenon depth of the vertical baffle should be equal to 2 / 3 of the thickness of the horizontal baffle, and the outer surface of the central hole of the horizontal baffle is reinforced by metal hoops, The hoop is provided with a bayonet, and the torsion of the torsion spring can be adjusted arbitrarily by turning the metal bar. Once the diameter of the torsion spring is known, the craftsmen can easily infer the size of the main components of the crossbow, and reinforce the key parts with metal. In 270 BC, the Ptolemaic dynasty perfected the theory of making catapults. They summed up two basic principles: for the catapult firing a spear, the optimal diameter of the torsion spring should be 1 / 9 of the length of the spear; for the catapult firing a stone bullet, the diameter (d) of the torsion spring should be equal to 1.1 times the cube root of the mass (M)., These two simple formulas contain the accurate understanding of the mechanical characteristics and ballistics of torsion spring. http://lplzcx.blogbus.com/logs/11316285.html

4. The spring calculation formula of torsion spring is:
torsion spring (kg) = elastic molus X-ray diameter X-ray diameter X-ray diameter / 3670 / pitch diameter / effective turns x torsion angle
conventional selection of elastic molus:
stainless steel-18500kg / mm
carbon steel-20000kg / mm
qingang-21000kg / mm
the force unit calculated by the above formula is kg. This formula is calculated as theoretical data, and finally needs to be confirmed and improved by actual proofing! Because this formula alone can not calculate all the details of the spring in detail, and these details have a great influence on the strength of the torsion spring
hope to help you! thank you!

5. Torsion spring

· spring constant: expressed by K, when the spring is twisted, every increase of 1 ° Load of torsion angle (kgf / mm)
· spring constant formula (unit: kgf / mm):
k = (e x D ^ 4) / (1167 x DM x P x n x R)

e = steel molus of wire rod: piano wire e = 21000, stainless steel wire e = 19400, phosphor bronze wire e = 11200, Brass wire e = 11200
d = wire diameter
do = od = od
Di = id = ID
DM = MD = pitch diameter = do-d
n = total number of turns
R = arm of force acting on load
P = 3.1416

6.

Formula: F = (ED ^ 4 *) ψ/ ( 3670 * n * d) * l

e: spring molus (generally 20000); d: Wire diameter; ψ: Torsion angle, N: effective turns, D: pitch diameter, l: torsion arm length

the torsion of a spring mainly depends on its elastic coefficient, which mainly depends on the material, cross-sectional area and the number of turns per unit length

The torsion spring belongs to spiral spring. The ends of the torsion spring are fixed to other components, and when the other components rotate around the center of the spring, the spring pulls them back to their original position, generating torque or rotating force. The torsion spring can store and release the angular energy or fix a device statically by rotating the arm around the middle axis of the spring body

extended data:

main parameters of torsion spring

(1) free length

(2) control diameter: outer diameter, inner diameter, inner diameter of casing, or outer diameter of round rod

(3) wire diameter

(4) materials (types and grades)

(5) number of turns: total number of turns and, right-handed or left-handed

(6) torsion force: the number of pounds deflected to a certain angle

(7) maximum deflection (angle from free position)

(8) terminal form

7. If you make the outer diameter 8.0, you can do it. If you make the outer diameter smaller, it's OK

8. For the design data of pressure spring
besides the spring size, it is more necessary to calculate the load of maximum load and displacement size; Spring constant: expressed by K, when the spring is compressed, the load (kgf / mm) for every 1 mm distance increase; Spring constant formula (unit: kgf / mm): k = (g) × d4)／8 × Dm3 × NC)
G = steel molus of wire rod: piano wire g = 8000; Stainless steel wire g = 7300; Phosphor bronze line g = 4500; Brass wire g = 3500 d = wire diameter do = od = outer diameter Di = id = inner diameter DM = MD = pitch diameter do-d n = total number of turns NC = effective number of turns = n-2
calculation example of spring constant: wire diameter = 2.0 mm, outer diameter = 22 mm, total number of turns = 5.5, steel wire material = piano wire
k = (G × d4)／8 × Dm3 × Nc＝8000 × 24／8 × two hundred and three × 3．5＝0．571kgf／mm
K=(G × d4)／8 × Dm3 × Nc＝8000 × 0.84／8 × six point six three × 2) = 1.34kgf / mm
3276.8/4599.936 = 0.712358 preload 0.65
when fixed, the compression is 2mm
tension spring
the K value of tension spring is the same as that of pressure spring
initial tension of tension spring: the initial tension is equal to the force required to properly pull apart the close springs and coils, and the initial tension occurs after the springs are rolled and formed. In the proction of tension spring, e to the different steel wire material, wire diameter, spring index, static electricity, grease, heat treatment, electroplating and so on, the initial tension of each tension spring is uneven. Therefore, when installing the tension spring of various specifications, it should be pre pulled until the distance between the parallel coils is slightly separated. The force required is called the initial tension. Initial tension = P - (k) × F1) = maximum load - (spring constant) × Tensile length) torsion spring
spring constant: expressed as K, when the spring is twisted, every 1 increase in the value of ° Load of torsion angle (kgf / mm). Formula of spring constant (unit: kgf / mm): k = (E) × d4)／1167 × Dm × p × N × R)
e = steel molus of wire: piano wire e = 21000, stainless steel wire e = 19400, phosphor bronze wire e = 11200, brass wire e = 11200 d = wire diameter do = od = outer diameter Di = id = inner diameter DM = MD = pitch diameter do DN = total number of turns r = arm of force under load p = 3.1416.

9. Your question is not clear.
according to what you said, it should be the pressure of the compression spring.
but the parameters you gave are not complete. What's the diameter of the wire? What kind of materials do you need to give< br />?
let me give you the general calculation formula of the tower. I don't know if it's what you want