What is the force of the cylinder

1.

Bottom area of cylinder inner diameter × System pressure = output force ----- n

for example: bore 40, system pressure 0.5MPa

20 × twenty ×π× 0.5 = 628n

thrust F1 on cylinder piston rod= π/ four × D2 × P ×&# 223; N)

tension on cylinder piston rod F2= π/ four × D2-d2 × P ×&# 223; N)

F1: push force when piston rod is pushed out

F2: pull force when piston rod is pulled back

D: inner diameter of cylinder pipe (piston diameter)

D: diameter of piston rod

P: air source pressure

& Load rate (at slow speed)= About 65% fast time= For example,

air pressure 0.5MPa (5.0985811kg force / square centimeter (kgf / cm))

cylinder diameter 50mm (5cm)

cylinder cross section = 3.14x (5 / 2) ^ 2 = 19.63 (square centimeter)

therefore, The theoretical output under 0.5MPa = 5.0985811 * 19.63 = 100.085 (KGF) can also be directly referred to the following cylinder output table

but it is only the theoretical output. Actually, it will be very fast to look up the table according to the working conditions

2.

Calculation formula of theoretical output force of cylinder: F = P * d-f ′

F: theoretical output force of cylinder (KGF)

F ′: output force at 85% efficiency (KGF) - (f ′ = f) × 85%)

D: cylinder diameter (mm)

P: working pressure (kgf / cm2)

3. Hello
first of all, your idea of mini punch is feasible
secondly, the power of the cylinder is compressed air. For household use, you need to buy an air pump with an air tank. I'm not sure what you mean by "point" or "air pump"
there is a piston in the middle of the cylinder, and the maximum force that the cylinder can achieve is equal to the proct of
piston area and the maximum allowable compressed air pressure (pressure).

4. The former formula does not consider the friction resistance F, while the latter one considers the friction resistance F. the latter one is more practical.

5. The following is the calculation formula of the theoretical output of the cylinder: F= π/ 4.10-2. D2. P
F
: theoretical output force of cylinder (KGF)
F & # 39;: Output force at 85% efficiency (KGF) -- (F & # 39; =) F × 85%)
D: cylinder diameter (mm)
P: working pressure (kgf / cm2)
the international unit of cylinder diameter is mm, the unit of piston area is QMM, that is mm

6. The cylinder diameter is R (mm), the air pressure is 5kg / cm, and the thrust is
(R / 20) * (R / 20) * 3.14 * 5

7. The cross-sectional area of the cylinder cavity is multiplied by the air pressure
cylinder diameter 16mm, 0.4MPa, thrust without rod cavity:
3.14 * 0.008 * 0.008 * 400000 = 80.384n (about 8kg thrust)
thrust with rod cavity (return force) should be smaller, and the piston rod diameter should be known before calculation
friction loss is not considered above.

8.

it can be calculated according to the calculation formula

9. The ratio of pressure to area is pressure

10. If you also know the actual air pressure, you can calculate it. For specific calculation formula, please refer to "pneumatic online" - very comprehensive pneumatic content