Formula for calculating deflection force

1. Photons have no static mass, but the dynamic mass of photons can be calculated by using the theory of relativity, so there will be interaction between the sun and photons (Universal Gravitation). Just think of photons as ordinary particles in motion
the specific questions seem to be the questions of the International Olympic Games of a certain year. The answers are quite detailed. I'll help you find them

2. Photons have momentum. According to the frequency of light and the photon energy formula, we can get the momentum of photons, calculate the mass of photons at this time, and then use the law of universal gravitation

3. Firstly, the motion is divided into latitude (the velocity is recorded as VX, the positive direction is the same as the rotation direction of the earth) and longitude (the velocity is recorded as vy, the positive direction is from south to North), and the radius of the earth is r, and the angular velocity of the earth is r ω， The mass of the object is m and the latitude is 0 θ All calculations ignore the revolution. If the object is stationary in the direction of latitude, its velocity relative to the sun is v0= ω* R*cos θ…… ① Centripetal force fn0 = V0 ^ 2 / (R * COS) θ)* M... ② at this time, it is relatively geostationary, so the resultant force is the centripetal force fn0, and the component of the force parallel to the earth is the component of the centripetal force parallel to the earth, that is, fn0 * sin θ When the object moves with the velocity VX along the latitude direction, the velocity relative to the sun is v = VX + V0, and it is subjected to the centripetal force FN & # 39= vx+v0)^2/(R*cos θ)* M... ③ at this time, the resultant force of gravity and supporting force of the earth remains unchanged in the direction parallel to the earth, and it is still fn0 * sin θ However, the centripetal force has changed to FN* sin θ If the earth is taken as the non inertial reference frame, the object is subjected to the inertial force: FN = FN & # 39* sin θ- fn0*sin θ…… ④ From (1) to (2) to (4): FN = (2vx * V0 + VX ^ 2) / (R * COS) θ)* M is also because of VX & gt& gt; So FN ≈ 2 * VX * V0 / (R * COS) θ)* m*sin θ= 2*vx* ω* m*sin θ Direction and FN; The direction is opposite, that is, the northern hemisphere is to the right and the southern hemisphere is to the left θ The linear velocity of the object at latitude is v0= ω* R*cos θ with θ Dv0 is derived from v0=- ω* R*sin θ d θ…… ① For the object moving along the meridian, the angular velocity in the direction of the meridian ω= d θ/ DT = vy / R... the dv0 = - vy will be obtained by bringing in ①* ω* sin θ DT is a = dv0 / dt = - vy* ω* sin θ And the velocity V of the object along the meridian also rotates with the rotation of the earth, and the acceleration is v* ω* sin θ， It is proved that the acceleration in the same direction, here is the acceleration of the earth relative to the object, then the acceleration of the object relative to the earth is a = vy* ω* sin θ+ v* ω* sin θ= 2*vy* ω* sin θ This is the acceleration proced by the Coriolis force, then the Coriolis force is f = m * a = 2vy* ω* m*sin θ The direction is the same as the rotation direction of the earth (all variables are positive), and then infer that the northern hemisphere is right and the southern hemisphere is left. Qualitative analysis: the closer to the equator, the greater the linear velocity is. If the velocity of the object in the latitude direction remains unchanged and moves along the longitude to the equator, the linear velocity of the object will be less than that of the earth, On the surface, it is slowed down by the geostrophic deflection force. At the same time, the velocity along the meridian itself changes with the rotation of the earth, and the acceleration direction is the same as the former. The same is true in other cases. When the object moves with velocity V (v = √ (VX ^ 2 + vy ^ 2)), it is subjected to Coriolis force F = m * √ (4 * VX ^ 2 + 4 * vy ^ 2)* ω* sin θ= 2mv* ω* sin θ， Direction: the northern hemisphere to the right, the southern hemisphere to the left, no force on the equator.

4. N = Sina / SINB (n is the refractive index, a is the angle of incidence, B is the angle of refraction)

5. f=2mv ω sin φ The following proof)
m is the mass of the object
F is the geostrophic deflection force
V is the horizontal velocity component of the object
V ω Is the angular velocity of the earth rotation
sin is a sine function
φ It is the latitude of the object

attached:
direction
perpendicular to the horizontal component of the object's velocity, the northern hemisphere to the right, the southern hemisphere to the left

geographical significance
has an impact on ocean currents, rivers, wind and other things with horizontal motion<

geostrophic deflection force and life
under the action of geostrophic deflection force, the movement direction of objects moving horizontally along the earth's surface deviates, which affects many natural phenomena and human proction and life. Here are five examples: (taking the northern hemisphere as an example)
1. The formation of water vortex
when we turn on the faucet to inject water into the plastic bucket, when the reservoir discharges water (the outlet is under water), when the sink discharges water, etc., we can see the formation of vortices on the water surface. It rotates clockwise ring water injection and anticlockwise ring water discharge< 2. Keep right for vehicles and pedestrians
not all countries or regions have right-hand traffic for vehicles and pedestrians, but right-hand traffic is the most reasonable< Third, the wear degree of left and right shoes is different
this phenomenon is difficult for modern people to see, because the time of wearing a pair of shoes is too short and the performance is not obvious. I think people over 40 still remember this phenomenon
this is e to the stress difference between the two shoes. In the northern hemisphere, e to the geostrophic force acting on the right side, it is often found that the wear of the right shoe is more than that of the left shoe; In the southern hemisphere, because of the geostrophic force acting on the left side, the wear of the left shoe is more than that of the right shoe< 4. Run counter clockwise on the track
when running on the track, people always like to run counter clockwise< 5. The mechanical equipment rotates clockwise
the electric fans, motors, diesel engines and water turbines we see all rotate clockwise.

6. Just use the international system of units.

7. Retrospection of Juye agricultural procts

8.

1、 Refractive index definition formula

formula expression: n = sin α/ sin β， Next, let's review the definition of refractive index:

when the light is refracted from the vacuum into the medium, the incidence angle will be smaller α Sine value and refraction angle of β The ratio of sine value (SIN) α/ sin β) Is a fixed value, called the "absolute refractive index" of the medium, referred to as "refractive index"

The

refractive index is represented by the symbol n. That is n = sin α/ sin β among α It is the angle of incidence when the light is refracted from the vacuum into the medium, β Is the refraction angle. It should be noted that, α Always greater than β， Therefore, the refractive index n is always greater than 1

Second, the supplementary formula of refractive index is

1, n = C / v

C refers to the speed of light in vacuum, and V refers to the speed of light in the medium

2、n=1/sinC

C refers to the critical angle of the medium

The refractive index of a medium is defined as the ratio n of the sine of the incident angle to the sine of the refraction angle when light is refracted from a vacuum into the medium. The refractive index of a medium is also equal to the ratio of the velocity C of light in vacuum to the velocity V of light in this medium. That is,

because the velocity C of light in vacuum is greater than the velocity V of light in any medium, the refractive index n of any medium is greater than 1. When light enters any medium from vacuum, the incidence angle is greater than the refraction angle

9.

The angle between the refraction ray and the normal is called the refraction angle. The refraction follows the law of refraction. The refraction angle is smaller than the incidence angle when the light slants into water or other media from air. When the incidence angle increases, the refraction angle increases with the increase of the incidence angle. When light from water or other medium oblique into the air, the refraction angle is greater than the incidence angle. When light enters vertically from air (or other medium), the direction of propagation does not change

refraction law of light: three lines are in the same plane, the normal line is in the middle, the angle in the air is large, and the light path is reversible

Refraction light, incident light and normal are in the same plane

The refracted light and incident light are separated on both sides of the normal

The refraction angle is smaller than the incidence angle when the light slants into water or other media from air. When the incidence angle increases, the refraction angle increases. The refraction angle is larger than the incidence angle when the light is slanted into the air from water or other medium. When the light is perpendicular to the air (or other medium), the propagation direction does not change

extended data

summary of light refraction law:

three lines and one side; Two line separation; The relationship between two angles can be divided into three cases:

1. When the incident light is perpendicular to the interface, the refraction angle is equal to the incident angle, and the incident angle is equal to 0 °

The refraction angle is smaller than the incidence angle when light is slanted into water from air

The refraction angle is larger than the incidence angle when the light slants into the air from water

applicable scope of refraction law:

this law is the basic experimental law of geometric optics. It is suitable for homogeneous isotropic media. The principle of the optical structure of various optical instruments used for controlling the optical path and imaging is mainly based on the law of refraction and reflection of light. This law can also be derived from the wave concept of light, so it can also be applied to the refraction of radio waves and sound waves

10. Sin (AI) / sin (AR) = (Ni) / (NR)
AI: incidence angle
ar: refraction angle
Ni: refractive index of incident medium
NR: refractive index of transmission medium