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How to calculate the force of cylinder

Publish: 2021-04-20 03:06:47
1.

Bottom area of cylinder inner diameter × System pressure = output force ----- n

for example: bore 40, system pressure 0.5MPa

20 × twenty ×π× 0.5 = 628n

thrust F1 on cylinder piston rod= π/ four × D2 × P ×&# 223; N)

tension on cylinder piston rod F2= π/ four × D2-d2 × P ×&# 223; N)

F1: push force when piston rod is pushed out

F2: pull force when piston rod is pulled back

D: inner diameter of cylinder pipe (piston diameter)

D: diameter of piston rod

P: air source pressure

& Load rate (at slow speed)= About 65% fast time= For example,

air pressure 0.5MPa (5.0985811kg force / square centimeter (kgf / cm))

cylinder diameter 50mm (5cm)

cylinder cross section = 3.14x (5 / 2) ^ 2 = 19.63 (square centimeter)

therefore, The theoretical output under 0.5MPa = 5.0985811 * 19.63 = 100.085 (KGF) can also be directly referred to the following cylinder output table

but it is only the theoretical output. Actually, it will be very fast to look up the table according to the working conditions

2.

Calculation formula of theoretical output force of cylinder: F = P * d-f ′

F: theoretical output force of cylinder (KGF)

F ′: output force at 85% efficiency (KGF) - (f ′ = f) × 85%)

D: cylinder diameter (mm)

P: working pressure (kgf / cm2)

3. The former formula does not consider the friction resistance F, while the latter one considers the friction resistance F. the latter one is more practical.
4. The following is the calculation formula of the theoretical output of the cylinder: F= π/ 4.10-2. D2. P
F
: theoretical output force of cylinder (KGF)
F & # 39;: Output force at 85% efficiency (KGF) -- (F & # 39; =) F × 85%)
D: cylinder diameter (mm)
P: working pressure (kgf / cm2)
the international unit of cylinder diameter is mm, the unit of piston area is QMM, that is mm
5. The cylinder diameter is R (mm), the air pressure is 5kg / cm, and the thrust is
(R / 20) * (R / 20) * 3.14 * 5
6. It's so simple. First of all, for the cylinder you selected, he will definitely provide the parameters of pushing and pulling force under how much pressure. If you can't calculate, I will give you a formula, f = PS = P * (PI) * r * r, the area of cylinder diameter for pushing out, the area of cylinder diameter for retracting minus the area of push rod. You can calculate the pushing and pulling force. As for pushing each other, I don't care if you don't interact with each other, you are just like a wall, and the forces on both sides are the same, How much on one side is how much on the other side. If one side is big and the other side is small, one side will definitely run. It's not whether it's one or not. It's interaction
7. The cross-sectional area of the cylinder cavity is multiplied by the air pressure
cylinder diameter 16mm, 0.4MPa, thrust without rod cavity:
3.14 * 0.008 * 0.008 * 400000 = 80.384n (about 8kg thrust)
thrust with rod cavity (return force) should be smaller, and the piston rod diameter should be known before calculation
friction loss is not considered above.
8. Static analysis is not, but if you consider motion, it's different. It involves mass (inertia)
9. < UL >
  • the pressure of the cylinder still needs to be determined according to the valve. If the valve can't bear it, no matter how much pressure your cylinder can bear, generally the valve is 3-8kg

    First, make a general calculation according to the rated air pressure and standard cylinder diameter

  • 10. 2.5 square* π* 6 = 117kg
    cylinder area * gas pressure
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