How do kinetic energy calculate force

1. If there is kinetic energy, there will be momentum. When momentum acts on an object, there will be impulse, which will proce force

2. 1/2m*v*v

3. Classical physical kinetic energy formula: EK = MV ^ 2 / 2. It is 700 * 13 * 13 / 2 = 59150 joules

4. Kinetic energy: 1 / 2mV & # 178
gravitational potential energy: MGH
elastic potential energy: 1 / 2kx & # 178;

5. Suppose the initial velocity V0 and the final velocity VT
of an object, then the average velocity is: VT + V0 / 2, The acceleration is: a = vt-v0 / T
F = ma = m * (vt-v0 / T)
s = (VT + V0 / 2) * t
W = FS = 1 / 2 * m * [(vt-v0) * (VT + V0)]
according to the square difference formula: w = 1 / 2 * m * (VT ^ 2-v0 ^ 2)
according to the kinetic energy theorem: the work done by combined force is equal to the change of kinetic energy w = 1 / 2 * m * VT ^ 2 - 1 / 2 * MV0 ^ 2
the kinetic energy of the object at the initial velocity V0 is: ek0 = 1 / 2 * m * V0 ^ 2 The kinetic energy at the final velocity VT is: ekt = 1 / 2 * m * VT ^ 2
perfect it:
the average velocity here is: VT + V0 / 2, which means the average velocity of uniform variable speed linear motion. What about variable speed motion
the average velocity formula can also be deced in this way, but to understand it in another way, first of all, it should be clear that the tangent does not pass through a point, but through two points, because two points determine a straight line, and the tangent is no exception, but these two points are infinitely close to each other. For a function image of velocity and time (arbitrary image), in a very short period of time, the initial velocity and the final velocity are infinitely close to each other on the function image. If a tangent is made, the slope (sine value) of the tangent is acceleration
A = vt-v0 / T
it can be considered that the motion is uniform in this limited short period of time, because the slope is constant, That is, the acceleration is fixed
therefore, the average velocity formula: VT + V0 / 2 can still be used.

6. When the body falls freely, gravity does positive work on the body, the gravitational potential energy decreases and the kinetic energy increases
the increase of kinetic energy is equal to the decrease of gravitational potential energy
if the gravity potential energy decreases by MGH, the kinetic energy increases by MGH.
because of the free fall, the initial kinetic energy is zero, so EK = MGH

7.

The kinetic energy expression EK = (MV ^ 2) / 2. Where m is the mass of the object and V is the velocity of the object

gravitational potential energy: EP = MGH. Where m is the mass of the object, G is the acceleration of gravity, and H is the height

definition of kinetic energy: the energy of an object e to its motion is called the kinetic energy of the object. Its size is defined as one-half of the proct of the mass of the object and the square of the velocity

gravitational potential energy is the energy possessed by an object e to the action of gravity. For gravitational potential energy, its size is determined by the relative position of the earth and the object on the ground. The greater the mass of the object, the higher the relative position and the more work it does, the greater the gravitational potential energy of the object. Its expression is: EP = MGH

extended data:

kinetic energy is scalar, without direction, only with size. And cannot be less than zero. It is consistent with work and can be directly added or subtracted

kinetic energy is a relative quantity, where V is related to the selection of reference frame. In different reference frames, V is different, and the kinetic energy of the object is also different

(1) the work done by a force to an object in a process is equal to the change of kinetic energy in the process

(2) the work done by the combined external force (the sum of the external forces on the object, according to the direction and the magnitude of the force, the direction and magnitude of the final resultant force of the object can be calculated by the orthogonal method) is equal to the change of the kinetic energy of the object

8. Rotational kinetic energy = (1 / 2) × J × W ^ 2
(where j is the moment of inertia of the regular body and W is the angular velocity)
the moment of inertia is equal to the sum of the proct of the mass of each mass element in the rigid body and the square sum of their respective vertical distances from the axis

9. It seems that you want to study collision. That is to say, the impacted object does not move or deform. What can be used to calculate the force is impulse I = f · t. Or do you want to use kinetic energy E = f · s< In a word, I think you should study steadily according to the system

10. By the question meaning: this question default sphere is the insulator, or does not consider the electrostatic inction
according to the conservation of energy: EK + kqq / 2R = kqq / R (because in the outer sphere, the potential generated by the outer sphere is equipotential, and it is useless to list in the equation, so simply omit)
the solution is EK = kqq / 2R