How to calculate the resistance

1. The maximum bending moment is: M = P (force) × A (distance)
section coefficient of rectangle w = a × b × b ÷ 6＝2 × eight × eight ÷ 6 = 21.33 (cm3)
allowable stress of material [ σ〕 Take 1550 (kgf / cm ^ 2) = M ÷ W＝P × A ÷ 21.33＝P × two hundred ÷ 21.33
P＝1550 ÷ two hundred × 21.33 = 165 (KGF)
note: from the microscopic point of view, as long as something is a little heavy, the steel plate will be bent and deformed. It's just a matter of the amount of bending deformation. Now I'll give you how much force the steel plate can bear, which is more in line with the reality.

2. Under the influence of external news and the pressure of the state, in fact, when there is a sharp drop, the return of high-quality currency will be very objective, which is also applicable to the stock market. Good fortune

3. Generally, the impact strength is tested by drop hammer impact strength. The impact strength of ordinary POM is 6. The impact strength with good toughness can reach 10-20, and the toughness of POM with good impact strength is better. It can be used at lower temperature

4. As for the shear calculation, it depends on what structure, what load, ever-changing
it must be said that the shear capacity of materials is related to the cross-section size of materials, physical properties of materials, load direction, load point and load size. The shear capacity is parallel to the section
shear resistance: the force that can resist shear. For example, the force perpendicular to the bolt axis in the bolt connection
stress: when the object is deformed e to external factors (stress, humidity change, etc.), the internal force of the interaction between the various parts of the object is generated to resist the effect of this external factor, and try to make the object return from the position after deformation to the position before deformation. The internal force per unit area at a point of the section under investigation is called stress. The normal stress or normal stress is perpendicular to the same section, and the shear stress or shear stress is tangent to the same section. The stress will increase with the increase of the external force. For a certain material, the increase of stress is limited. Beyond this limit, the material will be destroyed. For a certain material, the limit that the stress may reach is called the ultimate stress of the material. The ultimate stress value should be determined by the mechanical test of the material. The allowable stress is defined as the maximum stress that the material can work safely by appropriately recing the measured limit stress. In order to use the material safely, the stress in the material should be lower than its limit stress, otherwise the material will be destroyed in use
if it is the edge point of the section, let's set it as t, the interface torque M, the polar moment of inertia of the shaft as IP (P is the subscript, which is written as I below for the sake of avoiding misunderstanding). If the shaft diameter is d
then the calculation formula of T = m * (D / 2) / I
I is I = pi * (d ^ 4) / 32 (PI is the circumference
so the diameter is d = (16 * m / pi / T) ^ (1 / 3)

5. Tensile force F = sectional area * tensile strength = 50 * 50 / (4 * 3.14) * 460 = 91560.50955kn
ER.. is the unit of tensile strength wrong? Why is it so big? It should be 460n, mm2~

6. The uplift bearing capacity of the pile mainly depends on the material strength of the pile body, the uplift lateral resistance between the pile and soil, and the self weight of the pile body, but has no relationship with the reinforcement cage. It can be calculated according to the pile foundation specification.

7. The uplift bearing capacity of the pile mainly depends on the material strength of the pile body, the uplift lateral resistance between the pile and soil, and the self weight of the pile body, but has no relationship with the reinforcement cage. It can be calculated according to the pile foundation specification
calculation formula of reinforcement for pier column of reinforced pile foundation
No.1 reinforcement: number of one pier column: π×( 150-4 × 2) ÷ 11.5-1 = 38

number of bridges: 38 × 20 = 760, total length: (20683.2 + 212.4) × 20 × 38 = 9473.86m
total weight: 9473.86 × 3.85 = 36474.3kg

No.2 steel bar: length of each bar: π× 133.5 + 13 = 10807.5px
number of bridges: 16 × 4+5 × 2+4 × 2+3 × 2 = 108
total length: 4.323 × 108 = 466.88m total weight: 466.88 × 3.85 = 1797.5kg

No.3 steel bar: average length of each bar:
(3.14 × 146.5+3.14 ×( 146.5+3.53)
+3.14 ×( 146.5+3.53 × 2)
+3.14 ×( 146.5+3.53 × 3)
+3.14 ×( 146.5+3.53 × 4)
+3.14 ×( 146.5+3.53 × 5)
+3.14 ×( 146.5+3.53 × 6)
+3.14 ×( 146.5+3.53 × 7)
+3.14 ×( 146.5+3.53 × 8)
+3.14 ×( 146.5+3.53 × 9)
+10 × 5) ÷ 10
= 12880.000000000001px
number of bridges: 10 × 20 = 200
total length: 515.2 × 200 = 1030.40m total weight: 1030.40 × 0.617 = 635.8kg

No.4 reinforcement: length of left side of No.1 pier:
√ π× 1.43)2+0.12 ×( one hundred and ninety ÷ 2)+√( π× 1.43)2+0.22 ×[( 1127.9-190 × 2) ÷ 20]+ π× one point four three × 2 = 347.921m, average length 810710px, total 32428.4 × 20 = 6485.67m, total weight 6485.67 × 0.617 = 4001.7kg

No.6 steel bar: length of each steel bar: π× 155.5 + 14 = 12565px
number of piles: number of piles 1: [(66-52) - 1.4] ÷ two × 4 = 24; No.2, 3 and 4 reinforcement are the same as No.1

No.5 left reinforcement: [(69-55) - 1.4] ÷ two × 2 = 12

No.5 right reinforcement: [(71-55) - 1.4] ÷ two × 2 = 14
total: 24 × 4 + 12 + 14 = 122, total length: 122 × 5.026 = 613.17m total weight: 613.17m × 4.83 = 2961.6kg

No.7 steel bar: length of each bar: 134.7 × 3 = 10102.5px, 122 pieces are the same as No. 6 steel bar
total length: 122 × 4.041 = 493.002m total weight: 493.002 × 4.83 = 2381.2kg

No.8 steel bar: 1582712.5px 63308.5px × 20=12661.7m
12661.7 × 0.617 = 7812.3kg

No.9 reinforcement: length of each reinforcement: 30 + x2 = 1197.5px
number of the whole bridge: 122 × 4 = 488, total length: 488 × 479 = 233.752m total weight: 233.752 × 1.58=369.3kg

8.

For frame shear wall and frame tube structures, when the shear wall is the main component of lateral bearing capacity, its failure is very dangerous for the whole structure. The shear bearing capacity of story should be calculated with the yield shear bearing capacity of shear wall as the control condition, and the formula is as follows:

V iy = V isy + V if (5)

where V iy is the shear bearing capacity of story I; Visy is the yield shear capacity of shear wall on the first floor; If is the shear force proced by the frame column under the condition of deformation compatibility when the i-story shear wall is yielding

If there are multiple rows of vertical bars and horizontal bars in the shear wall, the anchorage measures of the intermediate horizontal bars at the corner are the same as those of the inner horizontal bars of the wall

extended data

1. For the fatigue calculation of steel structure, the allowable stress amplitude method is adopted, and the stress is calculated according to the elastic condition

The shear wall structure uses the reinforced concrete wallboard to replace the beam and column in the frame structure, which can bear the internal force caused by various loads and effectively control the horizontal force of the structure

The calculation method and diagram of shear wall structure are different with the type and opening size. The calculation diagram of integral wall and small opening integral wall is basically a single vertical cantilever rod

9. At present, the load structure model is mainly used in the calculation of underground structure in China, especially in the formwork lining. The interaction between lining and surrounding rock and the sharing of load are considered reasonably in this model, which embodies the design concept of safety and economy. It considers that under the interaction of surrounding rock and support, the surrounding rock not only provides active load, but also exerts passive reaction on the support structure. Because under the action of non-uniform active load, part of the supporting structure will deform towards the surrounding rock. When the stiffness of surrounding rock reaches a certain value, the surrounding rock will proce resistance to the lining structure to limit its deformation. Within a certain range, this resistance can be called elastic resistance. Therefore, based on Winkler's assumption of elastic foundation, the proportional coefficient of elastic reaction and deformation of tunnel is the elastic resistance coefficient The elastic resistance coefficient is usually determined by load plate test. From the relationship curve between pressure and settlement of load plate test, i.e. p-s curve, the proportional limit pressure and corresponding settlement can be obtained, and the elastic resistance coefficient can be obtained. The elastic resistance coefficient is different with the same grade of surrounding rock, different buried depth and nature of surrounding rock. Even in the same section of the tunnel, the vertical and horizontal elastic resistance coefficients are different. Therefore, the elastic resistance coefficient of surrounding rock can not be determined only by the grade of surrounding rock. The key is to do field test. The value range is generally 30 ~ 200MPa / m

10. Sectional area × The tensile strength is equal to the maximum force,