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PK calculation of longitudinal braking force of crane supported

Publish: 2021-04-24 01:02:11
1. The motion of crane on the crane beam proces three dynamic loads: vertical load, horizontal load and horizontal load along the longitudinal direction of the crane beam
the longitudinal horizontal load refers to the braking force of the crane, which is transmitted from the crane beam to the support between the columns along the track direction, and is not considered in the calculation of the cross section of the crane beam.
2. According to the load code for building structures (GB 5009), the standard value of crane longitudinal braking force should be 10% of the sum of the maximum wheel pressures of all braking wheels acting on one side of the track.
If only the support between columns is calculated, the axial force (pressure) of roof truss or rigid frame can be arranged at the corresponding position of column top, Then, the horizontal and longitudinal seismic forces are calculated according to the axial force (if calculated by software, the magnitude and calculation method are directly selected).
3. The standard value of wind load is obtained by multiplying the bearing area of the support by the wind pressure, which comes from the gables at both ends of the house (the shape coefficient is taken as the superposition of two sides). When the house has expansion joints, it comes from the gables at one end of the house (the shape coefficient of one side of the pressure area is taken as the shape coefficient). For the single span structure, the total wind load area can be taken as half of the gable cotton area (i.e. 1 / 2 span multiplied by the average height of gable); For multi span structure with inner column bracing, the total wind load area can be approximately taken as the sum of half of the span on both sides of the column row where the column bracing is located multiplied by the height of the column row
the longitudinal braking force of the crane acts on the contact point between the brake wheel and the track, and the standard value should be 10% of the sum of the maximum wheel pressures of all the brake wheels acting on one side of the track (generally, the number of brake wheels of each crane is half of the number of wheels on one side of the crane). The number of cranes should not be more than two, and the rection factor should be paid attention to
or watch http://wenku..com/view/8aa8a405cc17552707220852.html
the explanation is very detailed.
4. It's not calculated. Even if calculated, it can not be used as the design basis
crane instructions are available. If not, please provide it in writing
if not, please provide it
or, according to similar procts, but inform the owner.
5. The self weight multiplied by the maximum moving speed, the maximum static friction force and the reaction force are about the same
6. [answer] C
[answer analysis] textbook p73. As one of the components of the support system, the column support mainly bears the horizontal load, including the wind load from the gable, the longitudinal braking force of the crane and the longitudinal seismic force, which can strengthen the longitudinal stiffness and stability of the plant. And C answer, the lateral braking force of the crane is mainly borne by the crane beam.
7. Calculate the load between the columns. It's not dead load. Ha ha
If I guessed right. The horizontal force of the crane, along the longitudinal direction, is borne by the support between the columns. A section is made at the support between columns, and the component force of the axial force in the horizontal direction of the two support rods is balanced with the horizontal force of the crane, and the internal force of the support between columns is obtained. It can be assumed that the supporting pressure bar is out of work and can only be undertaken by the tension bar, so the calculation is simple.
8. The ability to resist the longitudinal horizontal force only depends on the bending capacity of single bent frame (column bottom rigid connection) is quite weak, so it is often necessary to transfer the longitudinal horizontal force to the foundation with the help of the shear capacity of the wall or the support between columns; And the support between columns is very helpful to increase the longitudinal stiffness. In addition, I think that the node rigid or not, has its own criteria, put here to discuss is not appropriate< The first step of calculation is to analyze the horizontal force (wind load, crane load and seismic force), and then calculate the design internal force of the supporting member by using the corresponding static diagram according to the arrangement of the support between the columns, And check the calculation according to the steel structure (if it is a concrete member, check the calculation according to the concrete code, and check the calculation according to the anti-seismic code).
9. The longitudinal braking force of the crane is 10% of the sum of the maximum wheel pressures of all braking wheels on one side of the crane.
10. The support between columns of steel structure is a connecting member set between two adjacent columns to ensure the overall stability of the building structure, improve the lateral stiffness and transfer the longitudinal horizontal force
the steel structure columns are supported by the frame columns of the steel structure workshop, and their functions are as follows:
1. Form a stable longitudinal frame to ensure the longitudinal stiffness of the steel structure workshop
2. Bearing the longitudinal force of the steel structure factory building and the wind load from the end gable, the longitudinal braking force of the crane should be uniformly transmitted to the foundation through the steel structure column support
3. Outside the plane of steel structure frame, provide reliable supporting points for steel structure workshop columns, and rece the calculation length of steel structure columns outside the plane of steel structure frame.
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