How to calculate the uplift force provided by anchor pile
Publish: 2021-04-25 04:38:16
1. Generally, the design value of pull-out bolt will exceed the actual stress value of bolt about 5 ~ 10 times···
2. The pull-out force is 1.3 times of the yield force
3. The uplift bearing capacity of the pile mainly depends on the material strength of the pile body, the uplift lateral resistance between the pile and soil, and the self weight of the pile body, but has no relationship with the reinforcement cage. It can be calculated according to the pile foundation specification.
4. The uplift bearing capacity of the pile mainly depends on the material strength of the pile body, the uplift lateral resistance between the pile and soil, and the self weight of the pile body, but has no relationship with the reinforcement cage. It can be calculated according to the pile foundation specification
calculation formula of reinforcement for pier column of reinforced pile foundation
No.1 reinforcement: number of one pier column: π×( 150-4 × 2) ÷ 11.5-1 = 38
number of bridges: 38 × 20 = 760, total length: (20683.2 + 212.4) × 20 × 38 = 9473.86m
total weight: 9473.86 × 3.85 = 36474.3kg
No.2 steel bar: length of each bar: π× 133.5 + 13 = 10807.5px
number of bridges: 16 × 4+5 × 2+4 × 2+3 × 2 = 108
total length: 4.323 × 108 = 466.88m total weight: 466.88 × 3.85 = 1797.5kg
No.3 steel bar: average length of each bar:
(3.14 × 146.5+3.14 ×( 146.5+3.53)
+3.14 ×( 146.5+3.53 × 2)
+3.14 ×( 146.5+3.53 × 3)
+3.14 ×( 146.5+3.53 × 4)
+3.14 ×( 146.5+3.53 × 5)
+3.14 ×( 146.5+3.53 × 6)
+3.14 ×( 146.5+3.53 × 7)
+3.14 ×( 146.5+3.53 × 8)
+3.14 ×( 146.5+3.53 × 9)
+10 × 5) ÷ 10
= 12880.000000000001px
number of bridges: 10 × 20 = 200
total length: 515.2 × 200 = 1030.40m total weight: 1030.40 × 0.617 = 635.8kg
No.4 reinforcement: length of left side of No.1 pier:
√ π× 1.43)2+0.12 ×( one hundred and ninety ÷ 2)+√( π× 1.43)2+0.22 ×[( 1127.9-190 × 2) ÷ 20]+ π× one point four three × 2 = 347.921m, average length 810710px, total 32428.4 × 20 = 6485.67m, total weight 6485.67 × 0.617 = 4001.7kg
No.6 steel bar: length of each steel bar: π× 155.5 + 14 = 12565px
number of piles: number of piles 1: [(66-52) - 1.4] ÷ two × 4 = 24; No.2, 3 and 4 reinforcement are the same as No.1
No.5 left reinforcement: [(69-55) - 1.4] ÷ two × 2 = 12
No.5 right reinforcement: [(71-55) - 1.4] ÷ two × 2 = 14
total: 24 × 4 + 12 + 14 = 122, total length: 122 × 5.026 = 613.17m total weight: 613.17m × 4.83 = 2961.6kg
No.7 steel bar: length of each bar: 134.7 × 3 = 10102.5px, 122 pieces are the same as No. 6 steel bar
total length: 122 × 4.041 = 493.002m total weight: 493.002 × 4.83 = 2381.2kg
No.8 steel bar: 1582712.5px 63308.5px × 20=12661.7m
12661.7 × 0.617 = 7812.3kg
No.9 reinforcement: length of each reinforcement: 30 + x2 = 1197.5px
number of the whole bridge: 122 × 4 = 488, total length: 488 × 479 = 233.752m total weight: 233.752 × 1.58=369.3kg
calculation formula of reinforcement for pier column of reinforced pile foundation
No.1 reinforcement: number of one pier column: π×( 150-4 × 2) ÷ 11.5-1 = 38
number of bridges: 38 × 20 = 760, total length: (20683.2 + 212.4) × 20 × 38 = 9473.86m
total weight: 9473.86 × 3.85 = 36474.3kg
No.2 steel bar: length of each bar: π× 133.5 + 13 = 10807.5px
number of bridges: 16 × 4+5 × 2+4 × 2+3 × 2 = 108
total length: 4.323 × 108 = 466.88m total weight: 466.88 × 3.85 = 1797.5kg
No.3 steel bar: average length of each bar:
(3.14 × 146.5+3.14 ×( 146.5+3.53)
+3.14 ×( 146.5+3.53 × 2)
+3.14 ×( 146.5+3.53 × 3)
+3.14 ×( 146.5+3.53 × 4)
+3.14 ×( 146.5+3.53 × 5)
+3.14 ×( 146.5+3.53 × 6)
+3.14 ×( 146.5+3.53 × 7)
+3.14 ×( 146.5+3.53 × 8)
+3.14 ×( 146.5+3.53 × 9)
+10 × 5) ÷ 10
= 12880.000000000001px
number of bridges: 10 × 20 = 200
total length: 515.2 × 200 = 1030.40m total weight: 1030.40 × 0.617 = 635.8kg
No.4 reinforcement: length of left side of No.1 pier:
√ π× 1.43)2+0.12 ×( one hundred and ninety ÷ 2)+√( π× 1.43)2+0.22 ×[( 1127.9-190 × 2) ÷ 20]+ π× one point four three × 2 = 347.921m, average length 810710px, total 32428.4 × 20 = 6485.67m, total weight 6485.67 × 0.617 = 4001.7kg
No.6 steel bar: length of each steel bar: π× 155.5 + 14 = 12565px
number of piles: number of piles 1: [(66-52) - 1.4] ÷ two × 4 = 24; No.2, 3 and 4 reinforcement are the same as No.1
No.5 left reinforcement: [(69-55) - 1.4] ÷ two × 2 = 12
No.5 right reinforcement: [(71-55) - 1.4] ÷ two × 2 = 14
total: 24 × 4 + 12 + 14 = 122, total length: 122 × 5.026 = 613.17m total weight: 613.17m × 4.83 = 2961.6kg
No.7 steel bar: length of each bar: 134.7 × 3 = 10102.5px, 122 pieces are the same as No. 6 steel bar
total length: 122 × 4.041 = 493.002m total weight: 493.002 × 4.83 = 2381.2kg
No.8 steel bar: 1582712.5px 63308.5px × 20=12661.7m
12661.7 × 0.617 = 7812.3kg
No.9 reinforcement: length of each reinforcement: 30 + x2 = 1197.5px
number of the whole bridge: 122 × 4 = 488, total length: 488 × 479 = 233.752m total weight: 233.752 × 1.58=369.3kg
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1. The watch with manual winding movement should be wound at the same time every day, so that the watch can operate with enough energy in the next 24 hours
2. The energy of the watch with automatic winding movement comes from the movement of the wearer's arm, so it is not necessary to manually wind the watch under normal wearing conditions. Only when the wearer's movement is not enough to add enough energy to the spring, the watch can be manually wound up, and the crown rotation is controlled within 20 turns
3. For an automatic winding watch that has not been worn for more than 40 hours, turn the crown for 20 turns to start the drive system of the movement again
4. In order to prevent moisture from seeping into the watch case and keep the watch waterproof, please make sure that the watch crown is always locked. Our address is room 1102, 11th floor, block D, Huaxi International Center, Chaoyang International Trade Center, Beijing
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