Address of Canada Visa Center in Shanghai
There are four visa centers of Canadian Embassy in China, namely Beijing, Shanghai, Guangzhou and Chongqing. The addresses of the visa centers are as follows:
in fact, the Pinyin spelling of Wuzhen has a certain meaning
W stands for wide connection
u stands for universal vision
Z stands for passionate ideas
< P > H stands for humanitarian caree stands for economic benefits
n stands for new future
these words can well summarize the core idea of Wuzhen World Internet Conference
the world Internet Conference, including Wuzhen Drama Festival, requires that the venue should have enough infrastructure to match, relevant hardware facilities can meet the standards, and have enough ability to accept participants from all over the world . Since the development of tourism in the 1990s, Wuzhen has increased investment in modernization on the basis of retaining the original classical buildings. After nearly 20 years of development, Wuzhen has complete infrastructure
bus line: Metro Line 1, the whole journey is about 8.1km
1. Walk about 600m from Guangzhou to gongyuanqian station
2. Take Metro Line 1, after 6 stops, to sports Center Station
3. Walk about 440m to wanlinghui
how much energy of the system is converted into internal energy after the bullet passes through the wood block: also the idea of the first question
q = f. △ s △ s is the relative displacement
1. Work done by friction on conveyor belt
W2 = - FX2 = - MV ^ 2
2. Work done by friction on object
W1 = FX1 = 1 / 2mV ^ 2
it is easy to know that the acceleration of the object is a = MGU / M = Gu = 10 * 0.3 = 3
it only takes t = 2 seconds for the object to reach v = 6m / s,
then the distance of two seconds is s = (1 / 2) * a * T ^ 2 = 0.5 * 3 * 4 = 6m
so, when the object is 6m away from m, it will be stationary relative to the belt, that is to say, the friction force will not work on the object in the later distance.
therefore, the work done by the belt on the friction force is the kinetic energy increment of the object.
that is, (1 / 2) MV ^ 2 = 0.5 * 3 * 6 ^ 2 = 54j
first, when the object is accelerating from static to v = 3m / s, it is subjected to a horizontal constant force F = 25N to the right and a friction force F = 0.25mg = 0.25 to the right × five × 10 = 12.5n
the resultant force is: 25 + 12.5 = 37.5n
the acceleration is 37.5 / 5 = 7.5m/s ^ 2
the time required is 3 / 7.5 = 0.4s and the displacement is 3 / 2 × 0.4 = 0.6m belt displacement 0.4 × 3 = 1.2m
the loss of mechanical energy is the work done by friction, which is equal to: (1.2m-0.6m) × 12.5 = 7.5 J (Note: relative displacement)
the second part is:
when the velocity exceeds v = 3m / s, the object is subjected to a rightward horizontal constant force F = 25N, but the friction force remains unchanged, but the direction changes to the opposite direction, - 12.5n
the resultant force is: 25-12.5 = 12.5n, the acceleration is: 12.5 / 5 = 2.5m/s ^ 2
calculate the time required for the second part 3 × t + 1/2 × two point five × T ^ 2 = 3.8-0.6
the solution is t = 0.8
the belt displacement is 3 × 8 = 2.4m, the displacement of the object is 3.2m,
the relative displacement is equal to 3.2-2.4 = 0.8m (Note: it is relative displacement)
the loss of mechanical energy is that the work done by friction is equal to 0.8m × 12.5 = 10 J
the total mechanical energy loss of the first part and the second part is 7.5 + 10 = 17.5 J
so the mechanical energy loss of the system is 17.5 J