How long does it take to transfer ownership to the housing tradi
Publish: 2021-04-25 18:24:07
1. You are the old and new district. In the New District, you can still sell some money to make cupboards. If you want to be self-sufficient, you can make toilets. The more advanced the others are, the worse they seem to be.... Kong Mingdeng has not studied it, so it's hard to say. Because the system is also sold, there is a ceiling, so it's impossible to make huge profits. The furniture profession in the old district has no future at present, so it is suggested to change. Let me tell you, if you want to make money as a profession, the simplest way is to do animal husbandry and mining. It doesn't need any trouble. Just do the task. And there's no need to think about raw materials at all. Now the difficulty of planting monsters has been reced. It's estimated that you can play. As for furniture, furniture making and pharmacy, the raw materials are taken from the above three professions, so it's more troublesome. The early upgrade is not as convenient as the above. In the later stage, it is more profitable to make a Fu, because a Fu only takes one hour. But it was very hard in the early days.
2.
Hi
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3. Recommendation 1: able to carry and control the hero lieyangleiona (non variation: dawn goddess)
the meat shield hero becomes lieyangleiona after the dawn goddess mutates. If the full score is ten, Xiaobian will give the meat shield hero ten. In the game, the Japanese girl is usually a six-star card with magic resistance. Therefore, she is good at restraining magic output heroes. The main move is solar flare, which is a semi control output skill. It can rece the movement speed of the opponent's hero within its range. Dawn shield belongs to the core skill of sunnu, which is equivalent to putting a damage rection shield on sunnu, and will cause damage to the hero within its range after the shield disappears. From the above five skills, we can see that Japanese women have two single point control skills, one range soft control skill, and another skill to shield and rece their own damage. They can carry and control. They must be recommended to you first.
the meat shield hero becomes lieyangleiona after the dawn goddess mutates. If the full score is ten, Xiaobian will give the meat shield hero ten. In the game, the Japanese girl is usually a six-star card with magic resistance. Therefore, she is good at restraining magic output heroes. The main move is solar flare, which is a semi control output skill. It can rece the movement speed of the opponent's hero within its range. Dawn shield belongs to the core skill of sunnu, which is equivalent to putting a damage rection shield on sunnu, and will cause damage to the hero within its range after the shield disappears. From the above five skills, we can see that Japanese women have two single point control skills, one range soft control skill, and another skill to shield and rece their own damage. They can carry and control. They must be recommended to you first.
4.
//26174;- 27426;- 36814;- br />
void welcome();< br />
//32479;- 33756;- 21333;
void mainmenu();< br />
//25143;
void openAnAccount();< br />
//38144;- 25143;
void closeAnAccount();< br />
//23384;- 27454;
void deposit();< br />
//21462;- 27454;
void withdraw();< br />
//d35810;
void query();< br />
//36134;- 25143;- 32452;- 32622;
int findAnAccount (int accNumber);< br />
//26174;- 36134;- 25143;- br />
void dispAnAccount (int i);< br />
//24080;= 21495< br />
int createAccNumber();< br />
//25226;- 32467;- 26500;- 32452;- 25454;- 208893;- br />
int writeData();< br />
//25226;- 25454;- 21040;- 32467;- 26500;- 32452;- br />
int readData();< <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<>//flag <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
//21435;- 38500;- 21491;- 26684;
char *right Trim (char *str);< br />
//26174;- 26377;- 36134;- 25143;
void queryall();< br />
//24471;- 21040;- 38190;- 24405;- 25143;- br />
void getaccName (char accNumber[]);< br />
//24471;- 21040;- 38190;- 24405;- br />
void getaccPWD (char accPWD[] < br />
//24471;- 21040;- 38190;- 24405;- br />
double getcash();< br />
//24471;- 21040;- 38190;- 24405;- 24080;- 21495;
int getaccNumber (int flag);< And if you want to />><<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
struct record
{
int accNumber;//
char accName[9];// char accPWD[7];// Double balance;// char flag[2];//
};< br />
//33258;- 25454;- br />
typedef struct record RECORD;< br />
//32467;= 26500;= 32452< br />
RECORD rs[N MAXREC NO];< br />
//36134;- 25143;- 32467;- 26500;- 32622;
int maxAccount =-1;// "22987;" "br" />
28304;"20998;
"35; include < stdio.h> br />
-35; include < string.h> br />
-35; include < stdlib.h> br />
-35; include < ctype.h> br />
-35; include < conio.h> br />
-35; includes " bank.h" br />
int main ()
{
char userName[9];< br />
char userPWD[7];< br />
int i;< br />
welcome();< br />
for (i = 0; and < 3; i+)
{
printf ("&35; 92? n"< br />
printf(" " < br />
scanf ("% s" userName;< br />
fflush (stdin);< br />
printf("35; 92? n"< br />
printf(" "< br />
scanf ("% s" userPWD);< br />
fflush (stdin);< br />
if ((strcmp(userName, " admin" (0) strcmp(userPWD, " admin") 0)
{
<25143;< 308304;26174;< 33756;< br /> mainmenu();< br />}
else
{
if (i < 2)
{
<25143;< 25110;< 38169;< 35823; 25143;< 367553;
printf(" "25143;" 25110;"38169;" 35823; 35831;"36755;" quot;< br />}
else
{
//36830;32493; 27425;36755;= 381693; 251103; 251104;-36864;- 32479br /> printf(" "25143;" 25110;"38169;" 35823; 36864;"324793d;< br />}
}
}
return 0;< br />}
void welcome ()
{
printf("+------------------------------------------------+&35; 92? n"< br /> printf(" 1244; &124;& 35; 92? n"< br /> printf(" 124s; "27426;" 36814;"20648;" 33988;"32508;" 21512;"19994;" 21153;"1244;"35992; n"< br /> printf(" 1244; &124;& 35; 92? n"< br /> printf("+----------------------------------------------+&35; 92? n"< br /> printf(" ^ "26364;" 36719;"29256;" 26435;"26377; 92? n"< br />}
//26174;- 32479;- 33756;- 21333;- br />void mainmenu()
{
int choice;< br />
choice =-1;< br />
to
{
printf("&35; 92? n"< br /> printf("+----------------------------------------------+&35; 92? n"< br /> printf(" 124s; 253844;27454435831;253531,25143335831;253534,1244;& 3535392; n"< br /> printf(" 124s; 21462;, 27454; 35831;, 25353; 2-38144;, 25143; 35831;, 25353; 5%1244;% 35392; n"< br /> printf(" 124s; "358101035831;" "253533333336864;" n"< br /> printf("+----------------------------------------------+&35; 92? n"< br />
printf(" "< br />
scanf ("% d" choice);< br />
fflush (stdin);< br />
switch (choice)
{
case 0:
exit (0);< br /> case 1:
deposit ();< br /> break;< br /> case 2:
withdraw ();< br /> break;< br /> case 3:
query ();< br /> break;< br /> case 4:
openAnAccount();< br /> break;< br /> case 5:
closeAnAccount();< br /> break;< br /> case 6:
queryall ();< br /> break;< br /> default:
printf(" (million ECU) br />
printf("35; 92? n"< br /> break;< br />}
}while (choice!= 0);< br />
maxAccount = 0;< br />}
//25143;
void openAnAccount ()
{
int accNumber; //
char accName[9]; //
char accPWD[7]; //
double cash; //
//22987;21464;< br /> accNumber = 0; < br />
memset(accName, 0, sizeof(accName);< br />
memset(accPWD, 0, sizeof(accPWD);< br />
cash = 0; < br />
<36134;= 21495;
accNumber = createAccNumber(); < br />
//33719;- 21462;- 24080;- 25143;- br /> getaccName(accName); < br />
//33719;- 21462;- 36134;- 25143; < br /> getaccPWD(accPWD); < br />
//33719;= 21462;= 23384;< br /> cash = getcash(0); < br />
maxAccount++;< br />
rs[maxAccount].accNumber = accNumber;//
strcpy(rs[maxAccount].accName,accName;//
strcpy(rs[maxAccount].accPWD,accPWD;//
rs[maxAccount].balance = cash;// "25226;" 27425;"25143;" 23384;"27454;" 23384;"32467;" 26500;"br />
strcpy(rs[maxAccount].flag," 0"// 25226;, 25143;, 36134;, 25143;, 29366;, 24577;, 23384;, 32467;, 26500;< br />
<26174;- 36134444;-25143d;-dispAnAccount(maxAccount);< br />
printf(" "25143;" 21151; 25353;"38190;" 36820;"22238; br />
printf ("35; 92? n"< br />
getch();< br />
return;< br />}
//26174;= 25143;/> void dispAnAccount(int i)
{
{
printf("+-------------------------------------------------------------------------------------+++&&d35; 92? n"< br /> printf("% 5s%124s;%-8s%-124s;%-6s%-124s;%4s%124s;%353592; n" quot; "" quot; "" quot; "" quot; "" quot; "< br /> printf("------+------------+--------------------+--------++++++&35; 92? n"< br /> printf(")1244;% 5d-124s;%-8s%-124s;%6s%124s;%12.2f%4s%1244s;&3535;92; n" rs[i].accNumber,rs[i].accName,rs[i].accPWD,rs[i].balance,act(s)flag? "" quot; (million) br /> printf("+----------------------------------------------------+&35; 92? n"< br />
}
//24080; 21495;
int createAccNumber ()
{
if (maxAccount =-1)
{
/> {24080; 21495; 1000122987;
return 10001;< br />}
else
{
//39034;24207; / 20135; 24080;= 21495< br /> return rs[maxAccount].accNumber + 1;//
}
//33719;= 21462;= 36134; 25143d;
void getaccName(char accName[]]
{
char caccName[100];//
int i;< br />
while (i)
{
memset (caccName, 0, sizeof(caccName);< br /> printf ("&35; 92? n"< br /> printf (" "35831;" 36755;"20648;" 25143;"25143;" quot;< br /> scanf ("% s" cacc);< br /> fflush(stdin);< br />
if (checkInput (0, caccName)
{
printf(" "36229;" "36807;" "25143;" "38271;" "24230;" "35; 92? n"< br /> continue;< br />}
and = 0;< br />}
memcpy (accName, caccName, 9);< br />}
//33719; 21462; 24080; 21495;< br />void getaccPWD (char accPWD[])
{
char caccPWD[100]; //
int i = 1;< br />
while (i)
{
memset (caccPWD, 0, sizeof (caccPWD);< br /> printf ("&35; 92? n"< br /> printf(" "35831;" 36755;"20648;" 25143;"quot;< br /> scanf ("% s" caccPWD);< br /> fflush(stdin);< br />
if (checkInput (1, caccPWD)
{
printf(" "36229;" "36807;" "38271;" "24230s;" "35; 92? n"< br /> continue;< br />}
and = 0;< br />
}
memcpy (accPWD, caccPWD, 7); < br />}
//33719; 21462; 23384;(21462; 27454;) br />double getcash (int flag)
{
char ccash[100]; //
double dcash; //
int i = 1;< br />
int j;< br />
wangman:while (i)
{
memset(ccash, 0, sizeof(ccash);< br />
dcash = 0;< br />
printf ("35; 92? n"< br />
switch (flag)
{
case 0: printf (" "35831;" 36755;"233844;"quot;"; < br /> break;< br />
case 1: printf(" "35831;" 36755;"21462;" 27454;" br /> break;< br />}
scanf ("% s" ccash);< br /> if ((checkInput(2, ccash)
{
printf(" "24405;" 36229;"36807;" 23384;"21462;" 38271;"24230; 35831;" 36755;"92; n"< br /> goto wangman;// "36755;" 19981;"21512;" 21040;"wangman" 26364; 21738;"25191;" 36755;"br />
"for (j = 0; j <= 99? j+)
{
if (!) ccash[j] > 39? 0&35;39; ccash[j] <= &35; 39? 9&35;39; "1244;"1244; ccash[j] == 35;39;35; 92? 0&35;39; "1244;"1244; ccash[j] == 35;39;.35; 39;)< br /> {
printf(" "36755;" 26377;"35823; 35831;" 20877;"27425;" 36755;"3535; 92; n"< br /> go
//26174;- 27426;- 36814;- br />
void welcome();< br />
//32479;- 33756;- 21333;
void mainmenu();< br />
//25143;
void openAnAccount();< br />
//38144;- 25143;
void closeAnAccount();< br />
//23384;- 27454;
void deposit();< br />
//21462;- 27454;
void withdraw();< br />
//d35810;
void query();< br />
//36134;- 25143;- 32452;- 32622;
int findAnAccount (int accNumber);< br />
//26174;- 36134;- 25143;- br />
void dispAnAccount (int i);< br />
//24080;= 21495< br />
int createAccNumber();< br />
//25226;- 32467;- 26500;- 32452;- 25454;- 208893;- br />
int writeData();< br />
//25226;- 25454;- 21040;- 32467;- 26500;- 32452;- br />
int readData();< <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<>//flag <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
//21435;- 38500;- 21491;- 26684;
char *right Trim (char *str);< br />
//26174;- 26377;- 36134;- 25143;
void queryall();< br />
//24471;- 21040;- 38190;- 24405;- 25143;- br />
void getaccName (char accNumber[]);< br />
//24471;- 21040;- 38190;- 24405;- br />
void getaccPWD (char accPWD[] < br />
//24471;- 21040;- 38190;- 24405;- br />
double getcash();< br />
//24471;- 21040;- 38190;- 24405;- 24080;- 21495;
int getaccNumber (int flag);< And if you want to />><<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
struct record
{
int accNumber;//
char accName[9];// char accPWD[7];// Double balance;// char flag[2];//
};< br />
//33258;- 25454;- br />
typedef struct record RECORD;< br />
//32467;= 26500;= 32452< br />
RECORD rs[N MAXREC NO];< br />
//36134;- 25143;- 32467;- 26500;- 32622;
int maxAccount =-1;// "22987;" "br" />
28304;"20998;
"35; include < stdio.h> br />
-35; include < string.h> br />
-35; include < stdlib.h> br />
-35; include < ctype.h> br />
-35; include < conio.h> br />
-35; includes " bank.h" br />
int main ()
{
char userName[9];< br />
char userPWD[7];< br />
int i;< br />
welcome();< br />
for (i = 0; and < 3; i+)
{
printf ("&35; 92? n"< br />
printf(" " < br />
scanf ("% s" userName;< br />
fflush (stdin);< br />
printf("35; 92? n"< br />
printf(" "< br />
scanf ("% s" userPWD);< br />
fflush (stdin);< br />
if ((strcmp(userName, " admin" (0) strcmp(userPWD, " admin") 0)
{
<25143;< 308304;26174;< 33756;< br /> mainmenu();< br />}
else
{
if (i < 2)
{
<25143;< 25110;< 38169;< 35823; 25143;< 367553;
printf(" "25143;" 25110;"38169;" 35823; 35831;"36755;" quot;< br />}
else
{
//36830;32493; 27425;36755;= 381693; 251103; 251104;-36864;- 32479br /> printf(" "25143;" 25110;"38169;" 35823; 36864;"324793d;< br />}
}
}
return 0;< br />}
void welcome ()
{
printf("+------------------------------------------------+&35; 92? n"< br /> printf(" 1244; &124;& 35; 92? n"< br /> printf(" 124s; "27426;" 36814;"20648;" 33988;"32508;" 21512;"19994;" 21153;"1244;"35992; n"< br /> printf(" 1244; &124;& 35; 92? n"< br /> printf("+----------------------------------------------+&35; 92? n"< br /> printf(" ^ "26364;" 36719;"29256;" 26435;"26377; 92? n"< br />}
//26174;- 32479;- 33756;- 21333;- br />void mainmenu()
{
int choice;< br />
choice =-1;< br />
to
{
printf("&35; 92? n"< br /> printf("+----------------------------------------------+&35; 92? n"< br /> printf(" 124s; 253844;27454435831;253531,25143335831;253534,1244;& 3535392; n"< br /> printf(" 124s; 21462;, 27454; 35831;, 25353; 2-38144;, 25143; 35831;, 25353; 5%1244;% 35392; n"< br /> printf(" 124s; "358101035831;" "253533333336864;" n"< br /> printf("+----------------------------------------------+&35; 92? n"< br />
printf(" "< br />
scanf ("% d" choice);< br />
fflush (stdin);< br />
switch (choice)
{
case 0:
exit (0);< br /> case 1:
deposit ();< br /> break;< br /> case 2:
withdraw ();< br /> break;< br /> case 3:
query ();< br /> break;< br /> case 4:
openAnAccount();< br /> break;< br /> case 5:
closeAnAccount();< br /> break;< br /> case 6:
queryall ();< br /> break;< br /> default:
printf(" (million ECU) br />
printf("35; 92? n"< br /> break;< br />}
}while (choice!= 0);< br />
maxAccount = 0;< br />}
//25143;
void openAnAccount ()
{
int accNumber; //
char accName[9]; //
char accPWD[7]; //
double cash; //
//22987;21464;< br /> accNumber = 0; < br />
memset(accName, 0, sizeof(accName);< br />
memset(accPWD, 0, sizeof(accPWD);< br />
cash = 0; < br />
<36134;= 21495;
accNumber = createAccNumber(); < br />
//33719;- 21462;- 24080;- 25143;- br /> getaccName(accName); < br />
//33719;- 21462;- 36134;- 25143; < br /> getaccPWD(accPWD); < br />
//33719;= 21462;= 23384;< br /> cash = getcash(0); < br />
maxAccount++;< br />
rs[maxAccount].accNumber = accNumber;//
strcpy(rs[maxAccount].accName,accName;//
strcpy(rs[maxAccount].accPWD,accPWD;//
rs[maxAccount].balance = cash;// "25226;" 27425;"25143;" 23384;"27454;" 23384;"32467;" 26500;"br />
strcpy(rs[maxAccount].flag," 0"// 25226;, 25143;, 36134;, 25143;, 29366;, 24577;, 23384;, 32467;, 26500;< br />
<26174;- 36134444;-25143d;-dispAnAccount(maxAccount);< br />
printf(" "25143;" 21151; 25353;"38190;" 36820;"22238; br />
printf ("35; 92? n"< br />
getch();< br />
return;< br />}
//26174;= 25143;/> void dispAnAccount(int i)
{
{
printf("+-------------------------------------------------------------------------------------+++&&d35; 92? n"< br /> printf("% 5s%124s;%-8s%-124s;%-6s%-124s;%4s%124s;%353592; n" quot; "" quot; "" quot; "" quot; "" quot; "< br /> printf("------+------------+--------------------+--------++++++&35; 92? n"< br /> printf(")1244;% 5d-124s;%-8s%-124s;%6s%124s;%12.2f%4s%1244s;&3535;92; n" rs[i].accNumber,rs[i].accName,rs[i].accPWD,rs[i].balance,act(s)flag? "" quot; (million) br /> printf("+----------------------------------------------------+&35; 92? n"< br />
}
//24080; 21495;
int createAccNumber ()
{
if (maxAccount =-1)
{
/> {24080; 21495; 1000122987;
return 10001;< br />}
else
{
//39034;24207; / 20135; 24080;= 21495< br /> return rs[maxAccount].accNumber + 1;//
}
//33719;= 21462;= 36134; 25143d;
void getaccName(char accName[]]
{
char caccName[100];//
int i;< br />
while (i)
{
memset (caccName, 0, sizeof(caccName);< br /> printf ("&35; 92? n"< br /> printf (" "35831;" 36755;"20648;" 25143;"25143;" quot;< br /> scanf ("% s" cacc);< br /> fflush(stdin);< br />
if (checkInput (0, caccName)
{
printf(" "36229;" "36807;" "25143;" "38271;" "24230;" "35; 92? n"< br /> continue;< br />}
and = 0;< br />}
memcpy (accName, caccName, 9);< br />}
//33719; 21462; 24080; 21495;< br />void getaccPWD (char accPWD[])
{
char caccPWD[100]; //
int i = 1;< br />
while (i)
{
memset (caccPWD, 0, sizeof (caccPWD);< br /> printf ("&35; 92? n"< br /> printf(" "35831;" 36755;"20648;" 25143;"quot;< br /> scanf ("% s" caccPWD);< br /> fflush(stdin);< br />
if (checkInput (1, caccPWD)
{
printf(" "36229;" "36807;" "38271;" "24230s;" "35; 92? n"< br /> continue;< br />}
and = 0;< br />
}
memcpy (accPWD, caccPWD, 7); < br />}
//33719; 21462; 23384;(21462; 27454;) br />double getcash (int flag)
{
char ccash[100]; //
double dcash; //
int i = 1;< br />
int j;< br />
wangman:while (i)
{
memset(ccash, 0, sizeof(ccash);< br />
dcash = 0;< br />
printf ("35; 92? n"< br />
switch (flag)
{
case 0: printf (" "35831;" 36755;"233844;"quot;"; < br /> break;< br />
case 1: printf(" "35831;" 36755;"21462;" 27454;" br /> break;< br />}
scanf ("% s" ccash);< br /> if ((checkInput(2, ccash)
{
printf(" "24405;" 36229;"36807;" 23384;"21462;" 38271;"24230; 35831;" 36755;"92; n"< br /> goto wangman;// "36755;" 19981;"21512;" 21040;"wangman" 26364; 21738;"25191;" 36755;"br />
"for (j = 0; j <= 99? j+)
{
if (!) ccash[j] > 39? 0&35;39; ccash[j] <= &35; 39? 9&35;39; "1244;"1244; ccash[j] == 35;39;35; 92? 0&35;39; "1244;"1244; ccash[j] == 35;39;.35; 39;)< br /> {
printf(" "36755;" 26377;"35823; 35831;" 20877;"27425;" 36755;"3535; 92; n"< br /> go
5.
bus line: No.368, about 2.6km
1. Walk about 180m from Ningbo passenger transport center to Ningbo passenger transport center station
2. Take No.368, pass 4 stops, and reach the temporary south bus station (Nanyuan Street) station (also take No.505, no.510)
3. Walk about 40m to Ningbo south bus station
6. Glory 6 is very good, you can go to the experience store to experience and query parameter information:
1. System: glory 6 adopts Huawei emui 2.3 (compatible with Android 4.4) operating system, equipped with Hisilicon Kirin 920 (Hisilicon Kirin), eight core: 4xa7 + 4xa15 processor
2. Camera: the rear camera is 13 million pixels, the front camera is 5 million pixels, and the photo resolution supports the main camera: 4160 × 3120 cameras: 2560 × 1920, let you take more different photos
3. Screen: the screen size is 5.0 inches, the screen color is 16 million colors, and the screen resolution is 1920x1080 445ppi. The three generations of canning gorillas are very clear whether they are watching videos or playing games.
1. System: glory 6 adopts Huawei emui 2.3 (compatible with Android 4.4) operating system, equipped with Hisilicon Kirin 920 (Hisilicon Kirin), eight core: 4xa7 + 4xa15 processor
2. Camera: the rear camera is 13 million pixels, the front camera is 5 million pixels, and the photo resolution supports the main camera: 4160 × 3120 cameras: 2560 × 1920, let you take more different photos
3. Screen: the screen size is 5.0 inches, the screen color is 16 million colors, and the screen resolution is 1920x1080 445ppi. The three generations of canning gorillas are very clear whether they are watching videos or playing games.
7.
Wildfight is a very interesting mobile game, which has attracted a large number of players since it was launched. The main reason is that the operation of this game is very simple, and it doesn't need too much thinking. Compared with other games, wildfight is more like a small game for leisure and wisdom. There are many heroes in this game, each hero has its own characteristics, and the game experience of each hero is also different< in my opinion, the heroes suitable for training are bull, colt and Rosa. These heroes perform very well in all aspects of the game. The specific introction is as follows:
I. bullin the wild fighting, the bull's hero has a very high burst damage in close range. According to my game experience, bull is especially suitable for charging at the front, Because the bull's weapon is a double barreled shotgun, when it is close to the enemy, the bull can do two shots and one enemy. So I really enjoy this feeling, and the bull's move can move a very long distance, which can not only be used to escape, but also be used to suppress the enemy's movement. If you want to experience the feeling of charging, you can try the hero of bull
you can comment on the heroes recommended in the wild fighting
8.
Bus route: Metro Line 2 → Metro Line 1, the whole journey is about 6.9km
1. Walk about 610m from Ningbo bus center station to passenger transport center station
2. Take Metro Line 2, pass 5 stations, reach Gulou station
3, walk about 280m, transfer to Metro Line 1
4. Take Metro Line 1, pass 1 station, reach dongmenkou (Tianyi Square) station
5, walk about 150m, Get to dongmenkou
bus line: Metro Line 2, the whole journey is about 6.9 km
1. Walk about 610 meters from Ningbo bus center station to passenger transport center station
2. Take Metro Line 2, after 5 stops, get to Gulou station
3. Walk about 1.0 km to dongmenkou
9. Write the value of dcash variable into ccash character array according to format
the total data occupies the first 12 digits of the array (including the decimal point), right aligned and left filled with spaces.
the total data occupies the first 12 digits of the array (including the decimal point), right aligned and left filled with spaces.
10. 1. Ke
applicable buff effect: all members increase attack power by 30%
Ke, a hero, is famous for reaping the head. As the most popular assassin in the game, Ke can also play a good effect in unlimited fighting mode! In addition, with the buff bonus, Aker can have more powerful harvesting ability
2. Guan Yu
buff effect: increase the movement speed of all members by 20%
Guan Yu still plays an eye-catching role in the unlimited scuffle mode. As long as Guan Yu runs, he can keep his attack shape, and the ADC heroes on the opposite side will become disabled blood. In addition, with the movement speed buff bonus, Guan Yu has been running very strong!
applicable buff effect: all members increase attack power by 30%
Ke, a hero, is famous for reaping the head. As the most popular assassin in the game, Ke can also play a good effect in unlimited fighting mode! In addition, with the buff bonus, Aker can have more powerful harvesting ability
2. Guan Yu
buff effect: increase the movement speed of all members by 20%
Guan Yu still plays an eye-catching role in the unlimited scuffle mode. As long as Guan Yu runs, he can keep his attack shape, and the ADC heroes on the opposite side will become disabled blood. In addition, with the movement speed buff bonus, Guan Yu has been running very strong!
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