Web3j Ethereum voting system

1. Ethereum also uses blockchain technology, but it is more convenient to use than bitcoin's blockchain Turing, which is complete and open source. Anyone can create their own application on the basis of Ethereum

2.

Blockchain projects require high efficiency, so most of the core source code development is using C / C + +. However, if you are doing a blockchain project, unless you need to make a lot of adjustments to the source code, you may not choose to use Java. For general DAPP applications, java development should also be a good choice. For example, in the case of Ethereum blockchain, there is a web3j class library for Java, which is very convenient; Bitcoin has bitcoin J class library, which is also easy to use. It still depends on the level of application, what to do, and the situation of the team

share two Java blockchain tutorials:

1. java bitcoin details

2. java Ethereum development

< / OL >

3. 客户端代码是这样的
#import "ViewController.h"
@implementation ViewController
-(void)aaa:(UIButton *)btn
{
NSString *method=[NSString stringWithFormat:@"login"];
NSString *username=[NSString stringWithFormat:@"123"];
笭肠蒂段郦灯垫犬叮华 NSString *password=[NSString stringWithFormat:@"123"];
NSString *urlString= [NSString stringWithFormat:@"",@"method=",method,@"username=",username,@"password=",password];

ASIFormDataRequest *requestForm = [[ASIFormDataRequest alloc] initWithURL:[NSURL URLWithString:urlString]];
//设置需要POST的数据，这里提交两个数据，A=a&B=b
//[requestForm setPostValue:@"a" forKey:@"A"];
//[requestForm setPostValue:@"b" forKey:@"B"];
[requestForm startSynchronous];

//输入返回的信息
NSLog(@"response\n%@",[requestForm responseString]);
[requestForm release];
}
- (void)viewDidLoad
{
[super viewDidLoad];
button1=[[UIButton alloc]initWithFrame:CGRectMake(200, 200, 50, 50)];
button1.backgroundColor=[UIColor redColor];
[self.view addSubview:button1];
[button1 addTarget:self action:@selector(aaa:) forControlEvents:UIControlEventTouchUpInside];
// Do any additional setup after loading the view, typically from a nib.
}
- (void)viewDidUnload
{
[super viewDidUnload];
// Release any retained subviews of the main view.
}
- (BOOL):(UIInterfaceOrientation)interfaceOrientation
{
return (interfaceOrientation != );
}
@end
客户端想要访问服务器
必须加上服务器的ip 服务端我是这样实现的
服务器是用java开发的
public
void doLogin(HttpServletRequest request,HttpServletResponse response) throws
IOException{
String
username=request.getParameter("username");
String
password=request.getParameter("password");
String
getStr=request.getParameter("A");
System.out.println("用户名:"+username+
"密码:"+password);
getAddr(request);
PrintWriter
out=response.getWriter();
String msg=null;
if(username!=null&&username.equals("123")&&password!=null
&&password.equals("123")&&
getStr!=null&&getStr.equals("a")){
msg="登陆成功";
}
else
{
msg="登陆失败";
}

out.print(msg);
out.flush();
out.close();
}