Mining and making money
Publish: 2021-05-01 13:46:22
1.
mining refers to the use of bitcoin mining machine to obtain bitcoin, that is, the computer used to earn bitcoin. If you can get bitcoin, you can make money this kind of computer generally has professional mining chips and works by installing a large number of graphics cards, which consumes a lot of power. The computer downloads the mining software and then runs a specific algorithm to get the corresponding bitcoin after communicating with the remote server
precautions:
1. It's better to use DIY mining machine, from purchasing accessories to assembly, and then to mining software, to learn, focus, practice and graally understand the blockchain
Mining is actually a fixed investment process: regardless of the currency price, a certain amount of positions will be increased every day3. The bitcoin wallet used to store bitcoin uses military level encryption, which makes it impossible for hackers to steal easily. Bitcoin wallet also allows users to set two passwords, a public account password and a private password. The user of public account password is to let the user receive bitcoin. If users want to withdraw or transfer bitcoin from their accounts, they need to use a private password
2. Cheat, pay money into the member first, dig the mine can't trade, can't withdraw cash, I am cheated
3. Bitcoin's computing power continues to rise today
according to bitinfocharts, the computing power of bitcoin network continues to rise today. Although bitcoin was unable to break through the $10000 price after its fall in February, the growing computing power in the past few months means that miners are increasingly interested in mining
in addition, whether mining makes money or not is related to computing power. If computing power is strong, the income will be high. Indivial mining can't make money now. It needs a certain scale of mining pool. If you encounter a good computing power platform, you can pay attention to it.
according to bitinfocharts, the computing power of bitcoin network continues to rise today. Although bitcoin was unable to break through the $10000 price after its fall in February, the growing computing power in the past few months means that miners are increasingly interested in mining
in addition, whether mining makes money or not is related to computing power. If computing power is strong, the income will be high. Indivial mining can't make money now. It needs a certain scale of mining pool. If you encounter a good computing power platform, you can pay attention to it.
4. It's very difficult to mine this year, because the currency price has dropped a lot. A few days ago, many mines were shut down. In addition, now mining is an instrialized and standardized instry, and there is almost no such thing as personal workshop mining to make a fortune. I suggest you give up this idea and really want to buy bitcoin. You can go to an exchange like okex, which is safe and convenient. Are you satisfied with my answer?
5. Hengjin is not mine, only mining magic iron ore, fine gold ore, krypton gold mine with out There is not much demand for magic iron at present. The market of refined gold is not good at present. There are too few krypton gold mines. The price is the highest. All maps of these three kinds of mines are available. Generally, the probability of ore coming out of caves is the highest. It's very convenient for sneakers! If you want to make money by mining, go to nagland. It's a recognized miner's paradise!
6. The excavated iron ore, silver, and so on can be made into iron ingots, silver ingots, etc.
Engineering and forging people will buy them for materials, and other gems can also be sold to the corresponding professional players
Engineering and forging people will buy them for materials, and other gems can also be sold to the corresponding professional players
7. Go to seal magic Valley to pick up rubbish to sell, or dig big medicine to sell Combined attack medicine)
8. 1、 Checking calculation of flexural bearing capacity (strength): the basic formula for calculating flexural bearing capacity of normal section of single reinforced rectangular section members is:
m ≤ Mu = FYAs (Ho FYAs / 2a1fcb)
when the concrete strength grade exceeds C50, A1 is taken as 1.0.
cross section strength of steel bar after replacement:
fy2as2 (ho2-fy2as2 / 2fcb) ≥ fy1as1 (ho1-fy1as1 / 2fcb)
FY2 --- design value of tensile strength of steel bar to be replaced
FY1 --- design value of tensile strength of original design steel bar
as2 --- cross section area of steel bar to be replaced
AS1 --- cross section area of original design steel bar
HO2 --- action point of resultant force of steel bar to be replaced member cross section The distance between compression edge
HO1 --- the distance between the action point of resultant force of original design reinforcement and compression edge of member section
FC --- design value of concrete compressive strength
b --- width of member section
II. Checking calculation of shear bearing capacity (strength) of steel bar replacement:
for reinforced concrete flexural members, when stirrups and bent reinforcement are provided, The calculation formula of the shear capacity of the inclined section is:
V ≤ 0.7ftbho + 1.25fyvasvho / S + 0.8fyastysin α s,
α S - the angle between the bending steel bar and the longitudinal axis of the component on the inclined section, generally taken as α s=45 °， When the beam section is high α s=60 °
that is to say, the shear force of reinforced concrete bending inclined section is mainly composed of three parts: 1; 2. The shear force of stirrup; 3. The shear force borne by the bent steel bar
among them,
the shear force borne by the stirrup is:
VSV = 1.25fyvasvho/s, so,
(1), the Stirrup replacement should meet the following requirements:
fyv2asv2 / S2 ≥ fyv1asv1 / S1
fyv2 --- design value of tensile strength of stirrup to be replaced
fyv1 --- design value of tensile strength of stirrup to be replaced
asv2 --- sectional area of stirrup to be replaced
ASV1 --- sectional area of stirrup to be replaced
S2 --- distance of stirrup to be replaced along the length of member
S1 --- distance of stirrup to be replaced along the length of member The shear force of
bending steel bar is:
VSB = 0.8fyasbsin α s. Therefore,
(2) After replacement, the bending reinforcement should meet the following requirements:
fy2asb2 ≥ fy1asb1
FY2 --- design value of tensile strength of bending reinforcement to be replaced
FY1 --- design value of tensile strength of original design bending reinforcement
asb2 --- cross-sectional area of bending reinforcement to be replaced in the same bending plane
asb1 --- cross-sectional area of original design bending reinforcement in the same bending plane
when fy2asb2 < fy1asb1, That is to say, when the resistance of the bent steel bar to be replaced is less than that of the original design, it can be strengthened by appropriately strengthening the stirrup< br />3、 Calculation of stirrup substitution:
fyv2asv2 / S2 ≥ fyv1asv1 / S1 + 2vj / 3ho
fyv2 --- design value of tensile strength of stirrup to be replaced
fyv1 --- design value of tensile strength of stirrup to be replaced
asv2 --- cross-sectional area of stirrup to be replaced
ASV1 --- cross-sectional area of stirrup to be replaced
S2 --- spacing of stirrup to be replaced along the length of member
S1 --- cross-sectional area of stirrup to be replaced along the length of member (4) calculation formula of rection value:
VJ = 0.8 (fy1asb1-fy2asb2) sin α S
3. Checking calculation of crack resistance of steel bar replacement:
calculation of maximum crack width of component:
ω max = α cr Ψσ sk(1.9c+0.08deq/ ρ te)Es
ω Max --- the maximum crack width of the component
α CR --- characteristic coefficient of member stress (for flexural member) α cr=2.1
Ψ--- The non-uniformity coefficient of longitudinal tensile steel bar strain between cracks
es --- elastic molus of steel bar
DEQ --- equivalent diameter of longitudinal steel bar in tensile zone, DEQ= Σ nid² i/ Σ ni υ idi
ρ Te --- reinforcement ratio of longitudinal tensile reinforcement calculated according to effective tensile concrete section area; In the calculation of maximum crack width, when ρ When te < 0.01,
is 0.01; ρ TE = (as + AP) / ate
C --- the distance from the outer edge of the outermost longitudinal tensile reinforcement to the bottom edge of the tensile zone (mm): when C < 20, take 20; When C > 6, 65
is selected Ψ＜ 2, 0; Ψ＞ When 1, take 1
for the members directly bearing repeated load, the Ψ= 1< br /> Ψ= 1.1-0.65ftk/ ρ te σ sk
σ Sk --- the stress of longitudinal tensile reinforcement of reinforced concrete calculated according to the standard combination of load effect σ Sk = MK / 0.87hoa
N1 * (3.14 * D1 ^ 2 / 4) * FY1 = N2 * (3.14 * D2 ^ 2 / 4) * FY2
n is the number of reinforcement
D is the diameter
FY1 is the strength of design reinforcement
FY2 is the strength of replacement reinforcement
m ≤ Mu = FYAs (Ho FYAs / 2a1fcb)
when the concrete strength grade exceeds C50, A1 is taken as 1.0.
cross section strength of steel bar after replacement:
fy2as2 (ho2-fy2as2 / 2fcb) ≥ fy1as1 (ho1-fy1as1 / 2fcb)
FY2 --- design value of tensile strength of steel bar to be replaced
FY1 --- design value of tensile strength of original design steel bar
as2 --- cross section area of steel bar to be replaced
AS1 --- cross section area of original design steel bar
HO2 --- action point of resultant force of steel bar to be replaced member cross section The distance between compression edge
HO1 --- the distance between the action point of resultant force of original design reinforcement and compression edge of member section
FC --- design value of concrete compressive strength
b --- width of member section
II. Checking calculation of shear bearing capacity (strength) of steel bar replacement:
for reinforced concrete flexural members, when stirrups and bent reinforcement are provided, The calculation formula of the shear capacity of the inclined section is:
V ≤ 0.7ftbho + 1.25fyvasvho / S + 0.8fyastysin α s,
α S - the angle between the bending steel bar and the longitudinal axis of the component on the inclined section, generally taken as α s=45 °， When the beam section is high α s=60 °
that is to say, the shear force of reinforced concrete bending inclined section is mainly composed of three parts: 1; 2. The shear force of stirrup; 3. The shear force borne by the bent steel bar
among them,
the shear force borne by the stirrup is:
VSV = 1.25fyvasvho/s, so,
(1), the Stirrup replacement should meet the following requirements:
fyv2asv2 / S2 ≥ fyv1asv1 / S1
fyv2 --- design value of tensile strength of stirrup to be replaced
fyv1 --- design value of tensile strength of stirrup to be replaced
asv2 --- sectional area of stirrup to be replaced
ASV1 --- sectional area of stirrup to be replaced
S2 --- distance of stirrup to be replaced along the length of member
S1 --- distance of stirrup to be replaced along the length of member The shear force of
bending steel bar is:
VSB = 0.8fyasbsin α s. Therefore,
(2) After replacement, the bending reinforcement should meet the following requirements:
fy2asb2 ≥ fy1asb1
FY2 --- design value of tensile strength of bending reinforcement to be replaced
FY1 --- design value of tensile strength of original design bending reinforcement
asb2 --- cross-sectional area of bending reinforcement to be replaced in the same bending plane
asb1 --- cross-sectional area of original design bending reinforcement in the same bending plane
when fy2asb2 < fy1asb1, That is to say, when the resistance of the bent steel bar to be replaced is less than that of the original design, it can be strengthened by appropriately strengthening the stirrup< br />3、 Calculation of stirrup substitution:
fyv2asv2 / S2 ≥ fyv1asv1 / S1 + 2vj / 3ho
fyv2 --- design value of tensile strength of stirrup to be replaced
fyv1 --- design value of tensile strength of stirrup to be replaced
asv2 --- cross-sectional area of stirrup to be replaced
ASV1 --- cross-sectional area of stirrup to be replaced
S2 --- spacing of stirrup to be replaced along the length of member
S1 --- cross-sectional area of stirrup to be replaced along the length of member (4) calculation formula of rection value:
VJ = 0.8 (fy1asb1-fy2asb2) sin α S
3. Checking calculation of crack resistance of steel bar replacement:
calculation of maximum crack width of component:
ω max = α cr Ψσ sk(1.9c+0.08deq/ ρ te)Es
ω Max --- the maximum crack width of the component
α CR --- characteristic coefficient of member stress (for flexural member) α cr=2.1
Ψ--- The non-uniformity coefficient of longitudinal tensile steel bar strain between cracks
es --- elastic molus of steel bar
DEQ --- equivalent diameter of longitudinal steel bar in tensile zone, DEQ= Σ nid² i/ Σ ni υ idi
ρ Te --- reinforcement ratio of longitudinal tensile reinforcement calculated according to effective tensile concrete section area; In the calculation of maximum crack width, when ρ When te < 0.01,
is 0.01; ρ TE = (as + AP) / ate
C --- the distance from the outer edge of the outermost longitudinal tensile reinforcement to the bottom edge of the tensile zone (mm): when C < 20, take 20; When C > 6, 65
is selected Ψ＜ 2, 0; Ψ＞ When 1, take 1
for the members directly bearing repeated load, the Ψ= 1< br /> Ψ= 1.1-0.65ftk/ ρ te σ sk
σ Sk --- the stress of longitudinal tensile reinforcement of reinforced concrete calculated according to the standard combination of load effect σ Sk = MK / 0.87hoa
N1 * (3.14 * D1 ^ 2 / 4) * FY1 = N2 * (3.14 * D2 ^ 2 / 4) * FY2
n is the number of reinforcement
D is the diameter
FY1 is the strength of design reinforcement
FY2 is the strength of replacement reinforcement
Hot content