Can BHC mine
Publish: 2021-04-16 23:11:57
1. Of course, it's against the law, but if we can't catch it, it's against the law just like the thief, but there are so many thieves. It's bad luck to catch him. There are many people who haven't caught him. We should be more vigilant
2. In theory, BCH can mine with graphics card, but graphics card mining has been eliminated as early as 2014. At present, BCH mining basically uses ant miner, that is, ASIC miner
BCH is a big block version of bitcoin and a small block version of BCE, which are competing for market leadership. BCH has performed well since its birth in August 2017. Recognized as a miracle by the coin circle.
BCH is a big block version of bitcoin and a small block version of BCE, which are competing for market leadership. BCH has performed well since its birth in August 2017. Recognized as a miracle by the coin circle.
3. ha-ha. It seems that the version has been changed. Blizzard won't let you brush mana. Then don't brush it. I'm 40 years old. I'll clear up the task of thorns valley. Go to the wasteland, the stone man at the bottom of map a.
4. British brands.
5. It's not good to eat but not to wear
6. 1. A mage is nothing more than learning to enchant, tailor and jewel
it's the best to learn jewelry, and it's also the most profitable major when jewelry reaches level 80. You can cut gems by yourself and earn money by cutting gems. But if you don't have a mining company, you'll spend more G on your own jewelry. And when changing equipment, in order to match attributes, gems are changed most
if you have less money, learn to be a tailor
as for alchemy, if you don't collect medicine by yourself, you can't make much money, and alchemy lasts one hour more than others
2. Now the mage SW graated, they are generally arcane. The talents are as follows:
http://zq.17173.com/wow/talents/wlk/talents.php?a=1&b=3&vars=0000000000000000
3. In the case of medium equipment, torture ice is the best. In the DPS, the output only needs brainless ice arrow, which is very easy. The talents are as follows:
http://zq.17173.com/wow/talents/wlk/talents.php?a=1&b=3&vars=3100230152201000
4. Arcane and ice have talent support that increases hit rate by 3%
if there are bird virtues or secret shepherds in the team who can strengthen the spirit fire, 139 hits will be enough. If the league has Delaney, just 127 hits
you need 177 hits if you don't have the bird virtue or dark shepherd of improved spirit fire. With Delaney, it's only 165 hits
the 12.6 hit level of legal system is 1% hit, and the basic hit rate of boss target is 83%, which requires 17% hit. As long as the team after the full buff, hit 17% on the line
then add other attributes by talent. Both arcane and ice have talent support. The critical hit rate is high enough, so you don't need to stack critical hits deliberately. After hitting the target, the damage is the best attribute, followed by speed. An attribute of heap is actually what kind of gem to use
gems of arcane and ice: red hole 12 damage (jewelry professional uses two 14 damage, Carlyle's rose and Julio's heart), yellow hole 5 rapid 6 damage, blue hole 5 spirit 6 damage
5. Any talent is a priority hit (after the hit reaches 17% in the team), and the benefit of magic injury is the biggest
both arcane and ice methods have a higher yield than critical hit
there is little difference between the critical hit and the rapid gain of fire method. If you feel lucky, you can't make a quick pile. If you're not lucky, stack critical hits to stabilize the critical hit rate
in the current version, only hits will overflow, that is, 17%, and more than 17% hits are useless attributes
the critical hit of legal profession will overflow only when it exceeds 100%
with haste, when your haste makes your spell release time less than 1 second, haste overflows. Because the skill is affected by the public CD, the mage's public CD is 1.5 seconds, which can be reced by heap haste, but it can only be reced to 1 second at most. If the release time of your ice arrow, aochong and other skills is less than 1 second, then the speed will overflow, because you have to wait for the public CD to complete before you can release the next skill.
it's the best to learn jewelry, and it's also the most profitable major when jewelry reaches level 80. You can cut gems by yourself and earn money by cutting gems. But if you don't have a mining company, you'll spend more G on your own jewelry. And when changing equipment, in order to match attributes, gems are changed most
if you have less money, learn to be a tailor
as for alchemy, if you don't collect medicine by yourself, you can't make much money, and alchemy lasts one hour more than others
2. Now the mage SW graated, they are generally arcane. The talents are as follows:
http://zq.17173.com/wow/talents/wlk/talents.php?a=1&b=3&vars=0000000000000000
3. In the case of medium equipment, torture ice is the best. In the DPS, the output only needs brainless ice arrow, which is very easy. The talents are as follows:
http://zq.17173.com/wow/talents/wlk/talents.php?a=1&b=3&vars=3100230152201000
4. Arcane and ice have talent support that increases hit rate by 3%
if there are bird virtues or secret shepherds in the team who can strengthen the spirit fire, 139 hits will be enough. If the league has Delaney, just 127 hits
you need 177 hits if you don't have the bird virtue or dark shepherd of improved spirit fire. With Delaney, it's only 165 hits
the 12.6 hit level of legal system is 1% hit, and the basic hit rate of boss target is 83%, which requires 17% hit. As long as the team after the full buff, hit 17% on the line
then add other attributes by talent. Both arcane and ice have talent support. The critical hit rate is high enough, so you don't need to stack critical hits deliberately. After hitting the target, the damage is the best attribute, followed by speed. An attribute of heap is actually what kind of gem to use
gems of arcane and ice: red hole 12 damage (jewelry professional uses two 14 damage, Carlyle's rose and Julio's heart), yellow hole 5 rapid 6 damage, blue hole 5 spirit 6 damage
5. Any talent is a priority hit (after the hit reaches 17% in the team), and the benefit of magic injury is the biggest
both arcane and ice methods have a higher yield than critical hit
there is little difference between the critical hit and the rapid gain of fire method. If you feel lucky, you can't make a quick pile. If you're not lucky, stack critical hits to stabilize the critical hit rate
in the current version, only hits will overflow, that is, 17%, and more than 17% hits are useless attributes
the critical hit of legal profession will overflow only when it exceeds 100%
with haste, when your haste makes your spell release time less than 1 second, haste overflows. Because the skill is affected by the public CD, the mage's public CD is 1.5 seconds, which can be reced by heap haste, but it can only be reced to 1 second at most. If the release time of your ice arrow, aochong and other skills is less than 1 second, then the speed will overflow, because you have to wait for the public CD to complete before you can release the next skill.
7. This bhc203 hair dryer is small and light. It can be taken with you when you are on a business trip. It has a negative ion design. The air collection nozzle can help you dry your hair quickly. It feels OK when you use it.
8. There should be several requirements: 1) magnetic energy proct 2) surface magnetic density 3) coating (Zn, Ni, electrophoresis, passivation) 4) material (if it is NdFeB, the grade is n30-n52; 30H——50H 30SH——50SH 28UH——40UH You can ask the magnet manufacturer to provide samples and parameters. Then make the drawings as your technical requirements. The manufacturer can ask the quality department to measure the receipt by the number of grams of iron absorbed (of course, it can't be controlled as a technical drawing, it's just a local method). Generally, the material can be NdFeB. In terms of structure, the size of magnetic force must be considered first, but the persistence of magnetic force must also be considered. After a long time, the magnetic force will drop and there will be no original strength. The disadvantage of NdFeB magnet is that the temperature performance is not good, the magnetic loss is large when it is used at high temperature, and the maximum working temperature is low. It's usually about 80 ℃. After special treatment, the maximum working temperature can reach 200 ℃, but the price is expensive.
9. Sanyo / Sanyo dg-f7526bhc 7.5kg
intelligent frequency conversion drying air washing drum washing machine rose gold LCD display 8.18 laundry bag official washing machine cover
latest quotation: ￥ 5499.00 [2014 / 8 / 24]
historical lowest price: ￥ 4590.00
main parameters
Proct Name: Sanyo washing machine dg-f7526bhc
brand: Sanyo
Model: dg-f7526bhc
Color: Rose Gold
Proct Type: roller
degree of automation: fully automatic
control mode: computer type
door opening mode: front opening mode
drainage mode: down drainage mode
display screen: LCD
inner barrel material: stainless steel
Box material: color steel
suitable for families of four or more
intelligent frequency conversion drying air washing drum washing machine rose gold LCD display 8.18 laundry bag official washing machine cover
latest quotation: ￥ 5499.00 [2014 / 8 / 24]
historical lowest price: ￥ 4590.00
main parameters
Proct Name: Sanyo washing machine dg-f7526bhc
brand: Sanyo
Model: dg-f7526bhc
Color: Rose Gold
Proct Type: roller
degree of automation: fully automatic
control mode: computer type
door opening mode: front opening mode
drainage mode: down drainage mode
display screen: LCD
inner barrel material: stainless steel
Box material: color steel
suitable for families of four or more
10. Cutting and calculation quantity of steel bar engineering in plane drawing:
I. beam (incomplete, to be supplemented later):
1. Welding is calculated according to binding length, and welding cost is not calculated separately in budget, and mechanical connection cost is determined by both parties through agreement< br />2. φ＞ At 12 o'clock, 8 meters each lap, φ When it is less than or equal to 12 meters, one lap is needed for 12 meters
3. The length of beam end infill zone (grade II) is 1.5hb. HB -- beam height
4. The stirrups in the binding lap area should be densified, and there is no requirement for stirrup densification in mechanical connection
5 φ Within 10 and φ There are two kinds of billing except 10
6. According to the latest 03g101 atlas, the first skin and the second skin of the length of the bearing negative reinforcement extending into the beam are taken as 1 / 3 of the length of the larger span (the original atlas stipulates that the length of the bearing negative reinforcement extending into the beam is taken as 1 / 3 of the length of the larger span, and the second skin is taken as 1 / 4 of the length of the larger span).
2 Slab:
slab reinforcement mainly includes:
1) stressed reinforcement (unidirectional, bidirectional, single-layer and double-layer)
2) bearing negative reinforcement
3) distributed reinforcement
4) additional reinforcement (additional radial reinforcement at the corner, additional reinforcement at the opening)
5) supporting reinforcement (upper and lower layers are supported in case of double-layer reinforcement)
1. Stressed reinforcement:
length of bottom reinforcement L = net length + Max {B / 2, 5D} of left support + Max {B / 2, 5D} of right support + hook at both ends (if it is grade I reinforcement)
length of gluten L = net length + 2 La (both ends are end supports)
b-width of support, d-diameter of reinforcement
number = (net length dection) / reinforcement spacing + 1
2. Negative reinforcement and distributed reinforcement of support:
negative reinforcement length = Design negative reinforcement length + left bending + right bending [plate thickness - 2 × Protective layer (only one protective layer is reced in budget)]
number of negative reinforcement = reinforcement range / reinforcement spacing + 1
length of distributed reinforcement: there are three calculation methods:
1) and lap length of negative reinforcement (either 150 lap length or 250 minimum anchorage length or 300 minimum lap length)
2) according to the length of the axis
3) calculated according to the length of negative reinforcement arrangement range
all the above three methods are OK, but the first method is preferred
3. Additional reinforcement (additional radial reinforcement at corner, additional reinforcement at opening) and supporting reinforcement (upper and lower layers are supported when double-layer reinforcement):
length of additional reinforcement = Design marked length + left bending + right bending [plate thickness - 2 × Protective layer (only one protective layer is reced in budget)]
(Note: sometimes the length of radial reinforcement at the corner decreases graally from the corner to both sides)
supporting reinforcement is a measure to ensure the position of upper reinforcement of double-layer reinforcement. Generally, one reinforcement (stacking stool) is arranged every 1 m, the specification is one specification larger than the plate reinforcement, and the length is the clear span length of the span, The length of the supporting legs is twice of the thickness of the plate minus the protective layer, and the leg spacing is 1m< The calculation method of the length of the main reinforcement is the same as that of the frame beam, but the upper reinforcement and the lower reinforcement are reversed
A = 1.2la + HB + 0.5hc
HB -- section height of foundation girder
HC section width along the span direction of foundation beam
the first row and the second row are Lo / 3. When there are more than two rows of steel bars, the design should indicate the size, and L1 and L2 should take the larger value<
II) stirrup:
four limb hoop (big hoop sleeve small hoop):
1) calculation method of cutting length of big Hoop:
(2H + 2b) - 8bhc + 4D + 4 × Bend adjustment value + 2 × 9 d (blanking)
(2H + 2b) - 8bhc + 8D + 2 × 11.9d (budget)
2) calculation method of reinforcement length of small hoop:
one of them:
L (reinforcement length) = [(b-2bhc-d) / 3 + D] × 2+H-2bhc × 2+2 × 11.9d+4d+4 × Bending adjustment value (blanking)
L (reinforcement length) = [(b-2bhc-d) / 3 + D] × 2+H-2bhc × 2+2 × 11.9d + 8D (budget)
Second:
L (reinforcement length) = [(b-2bhc-d) / 4 × 2+D] × 2+H-2bhc × 2+2 × 11.9d+4d+4 × Bending adjustment value (blanking)
L (reinforcement length) = [(b-2bhc-d) / 4 × 2+D] × 2+H-2bhc × 2+2 × 11.9d + 8D (budget)
Third:
L (reinforcement length) = [(b-2bhc-d) / 5 + D] × 2+H-2bhc × 2+2 × 11.9d+4d+4 × Bending adjustment value (blanking)
L (reinforcement length) = [(b-2bhc-d) / 5 + D] × 2+H-2bhc × 2+2 × 11.9d + 8D (budget)
Description: 1. D-diameter of longitudinal bar; D -- stirrup diameter; BHC -- protective layer
B-BEAM width; H -- beam height
2. Stirrup hook (135 degrees): 11.9d for seismic, 6.9d for non seismic (grade I reinforcement)
calculation formula of hook length (r = 1.25d):
(1.25 + 0.5) d × one hundred and thirty-five ×(π/ 180) - (1.25 + 1) d + length of straight section (the larger value of anti-seismic is 10d or 75mm, and that of non anti-seismic is 5d)
≈ 1.9d + length of straight section (i.e. 11.9d or 6.9d)
3. Calculation formula of bending adjustment value (90 degrees) (bending radius R is 1.25d):
(1.25 + 0.5) d × ninety ×(π/ 180)-(1.25+0.5)d × 2 ≈ - 0.75D
4. The 135 degree hook of slab member is 6.9d (all as non seismic), and the stirrup hook of bottom slab beam is 11.9d, but the stirrup is not required to be densified (the rest of the bottom slab reinforcement is designed as non seismic)
5. The short reinforcement is laid first, and then the long reinforcement is laid< Four, sump: (omitted)
five, column:
one) concept: according to the different location:
corner column, side column, middle column
the reinforcement in the column is divided by location:
1, bottom layer reinforcement
2, middle layer reinforcement
3 Top layer reinforcement:
(1) beam reinforcement
(2) edge reinforcement
(3) far beam reinforcement
note: beam reinforcement: the reinforcement on the side of the nearest bending beam
to the near rib: bend to the opposite side far away from it
far beam reinforcement: the reinforcement of the beam bending to the far side< Calculation:
1. The number of reinforcement in the column section = 2 × I + J) - 4
i-number of longitudinal load-bearing bars in horizontal row
J-number of longitudinal load-bearing bars in vertical row
2. Foundation layer:
foundation joint bar = thickness of foundation slab - protective layer + length of bars extending into upper layer + bending length a
column Comparison table of anchorage vertical length and hook length of wall joint bar:
anchorage vertical length hook length a
≥ 0.5lae (≥ 0.5la) 12D and ≥ 150
≥ 0.6lae (≥ 0.6la) 10d and ≥ 150
≥ 0.7lae (≥ 0.7la) 8D and ≥ 150
≥ 0.8lae (≥ 0.8la) 6D and ≥ 150
length of foundation and first floor column bar (including first floor and foundation joint bar)= Thickness of foundation slab - protective layer + length of reinforcement extending into upper layer (first layer) + bending length a + height of first layer + length of reinforcement extending into upper layer [see (03g101-1) p42 for length of reinforcement extending into upper layer]
3. Middle layer:
1) column longitudinal reinforcement:
length of longitudinal reinforcement L = storey height - height of this layer extending out of ground + height of upper layer extending out of floor + lap length (if yes) Mechanical connection or welding does not need to add lap length, only add welding shrinkage length adjustment value)
2) stirrup:
stirrup blanking length L = (2H + 2b) - 8bhc + 4D + 4 × Bend adjustment value + 2 × 9 d
effective length of stirrup L = (2H + 2b) - 8bhc + 8D + 2 × 9 d
Description: d-diameter of longitudinal bar; D -- stirrup diameter; BHC -- protective layer
B -- column section width; H -- column section height
★ note: at this time, the bending adjustment value is mostly negative
the blanking and calculation length of the small hoop of the big hoop and small hoop are the same as that of the beam small hoop
number of stirrups = (range length of densified zone / densified spacing) + (range length of non densified zone / non densified spacing) + 1
3) general regulations of densified zone of column:
1 there are three densified zones of column stirrups on the first floor (the first floor here refers to the first floor on the foundation, not necessarily the first floor) ± For the first floor calculated from 0.000, it can also be basement):
a. the length of the stirrup densification area in the lower part is HN / 3
B. the length of the upper stirrup densification zone is Max {500, the dimension of the long side of the column HC, HN / 6}
C. densification within the range of beam joints
note: if the longitudinal reinforcement of the column is bound and lapped, the lapped range shall be increased (the same below)< The length of the upper stirrup densification area is Max {500, the dimension of the long side of the column HC, HN / 6}
B. densification within the range of beam joints
C. the lower part is the same as the upper part
note: if the longitudinal reinforcement of the column is bound and lapped, the lapped range shall be increased (the same below)
HC -- the dimension of the long side of the column; HN the net height of the column< Top column:
the top column is divided into corner column, side column and middle column (middle column)
1) corner column:
longitudinal reinforcement length = floor clear height - reinforcement height of this floor extending out of the ground + anchorage length of top reinforcement (see the following description for the anchorage length of longitudinal reinforcement outside the top column, When welding or mechanical connection)
length of longitudinal reinforcement = clear height of the floor - height of the reinforcement extending out of the ground of the floor + anchorage length of the top reinforcement + binding lap length (the anchorage length of the longitudinal reinforcement outside the top column is shown in the following description. Binding is usually used in budget. If mechanical connection or welding is adopted, the welding or mechanical connection cost is calculated separately according to the agreement of both parties, (excluding lap length)
★ note:
○ 1 internal measurement of reinforcement anchorage length:
A. direct anchor: beam height - protective layer ≥ Lae (LA): beam height - protective layer
B. bending anchor: beam height protective layer < Lae (LA): beam height protective layer + 12D< (2) anchorage length of outer reinforcement:
A. first layer of column top:
A): ≥ 1.5lae (overlapped with longitudinal reinforcement at the upper part of beam)
b): ≥ beam height - protective layer + column width - protective layer + 8D (bending into the inner side of column)
B. the second layer of column top: ≥ beam height - protective layer + column width - protective layer + 8D.
note: the anchorage length of outer reinforcement = max {1.5 Lae, Beam height - protective layer + column width - protective layer}
[see (03g101-1) P37 (seismic) or p43 (non seismic) for details and other instructions
2) side column:
(diagonal column)
3) middle column:
longitudinal reinforcement L = net height of column HN - height of this floor above ground + anchorage length of top layer (if it is lapped, it shall be lapped)
anchorage length value:
○ 1 straight anchor (when beam height protective layer ≥ LAE): beam height protective layer<
2 bending anchor (beam height - protective layer < LAE): beam height - protective layer + 12D.
precautions:
1 when the upper column has more reinforcement than the lower column, the more reinforcement should be inserted into the lower column 1.2lae When the upper column reinforcement is larger than the lower column reinforcement, the upper column reinforcement should extend into the lap joint area of the lower column to lap
3 when the upper column reinforcement is smaller than the lower column reinforcement, the lower column reinforcement should extend into the lap joint area of the upper column to lap
in note 0 2, move the connection position of the lower end up to the upper end of the column (see 03g101-1 p42)
the reinforcement of the lower column more than that of the upper column should extend to 1.2lae (including beam)
(see Figure 1, figure 3 and notes of 03g101-1 p42 for details)
VI. wall:
I) classification of wall:
1
I. beam (incomplete, to be supplemented later):
1. Welding is calculated according to binding length, and welding cost is not calculated separately in budget, and mechanical connection cost is determined by both parties through agreement< br />2. φ＞ At 12 o'clock, 8 meters each lap, φ When it is less than or equal to 12 meters, one lap is needed for 12 meters
3. The length of beam end infill zone (grade II) is 1.5hb. HB -- beam height
4. The stirrups in the binding lap area should be densified, and there is no requirement for stirrup densification in mechanical connection
5 φ Within 10 and φ There are two kinds of billing except 10
6. According to the latest 03g101 atlas, the first skin and the second skin of the length of the bearing negative reinforcement extending into the beam are taken as 1 / 3 of the length of the larger span (the original atlas stipulates that the length of the bearing negative reinforcement extending into the beam is taken as 1 / 3 of the length of the larger span, and the second skin is taken as 1 / 4 of the length of the larger span).
2 Slab:
slab reinforcement mainly includes:
1) stressed reinforcement (unidirectional, bidirectional, single-layer and double-layer)
2) bearing negative reinforcement
3) distributed reinforcement
4) additional reinforcement (additional radial reinforcement at the corner, additional reinforcement at the opening)
5) supporting reinforcement (upper and lower layers are supported in case of double-layer reinforcement)
1. Stressed reinforcement:
length of bottom reinforcement L = net length + Max {B / 2, 5D} of left support + Max {B / 2, 5D} of right support + hook at both ends (if it is grade I reinforcement)
length of gluten L = net length + 2 La (both ends are end supports)
b-width of support, d-diameter of reinforcement
number = (net length dection) / reinforcement spacing + 1
2. Negative reinforcement and distributed reinforcement of support:
negative reinforcement length = Design negative reinforcement length + left bending + right bending [plate thickness - 2 × Protective layer (only one protective layer is reced in budget)]
number of negative reinforcement = reinforcement range / reinforcement spacing + 1
length of distributed reinforcement: there are three calculation methods:
1) and lap length of negative reinforcement (either 150 lap length or 250 minimum anchorage length or 300 minimum lap length)
2) according to the length of the axis
3) calculated according to the length of negative reinforcement arrangement range
all the above three methods are OK, but the first method is preferred
3. Additional reinforcement (additional radial reinforcement at corner, additional reinforcement at opening) and supporting reinforcement (upper and lower layers are supported when double-layer reinforcement):
length of additional reinforcement = Design marked length + left bending + right bending [plate thickness - 2 × Protective layer (only one protective layer is reced in budget)]
(Note: sometimes the length of radial reinforcement at the corner decreases graally from the corner to both sides)
supporting reinforcement is a measure to ensure the position of upper reinforcement of double-layer reinforcement. Generally, one reinforcement (stacking stool) is arranged every 1 m, the specification is one specification larger than the plate reinforcement, and the length is the clear span length of the span, The length of the supporting legs is twice of the thickness of the plate minus the protective layer, and the leg spacing is 1m< The calculation method of the length of the main reinforcement is the same as that of the frame beam, but the upper reinforcement and the lower reinforcement are reversed
A = 1.2la + HB + 0.5hc
HB -- section height of foundation girder
HC section width along the span direction of foundation beam
the first row and the second row are Lo / 3. When there are more than two rows of steel bars, the design should indicate the size, and L1 and L2 should take the larger value<
II) stirrup:
four limb hoop (big hoop sleeve small hoop):
1) calculation method of cutting length of big Hoop:
(2H + 2b) - 8bhc + 4D + 4 × Bend adjustment value + 2 × 9 d (blanking)
(2H + 2b) - 8bhc + 8D + 2 × 11.9d (budget)
2) calculation method of reinforcement length of small hoop:
one of them:
L (reinforcement length) = [(b-2bhc-d) / 3 + D] × 2+H-2bhc × 2+2 × 11.9d+4d+4 × Bending adjustment value (blanking)
L (reinforcement length) = [(b-2bhc-d) / 3 + D] × 2+H-2bhc × 2+2 × 11.9d + 8D (budget)
Second:
L (reinforcement length) = [(b-2bhc-d) / 4 × 2+D] × 2+H-2bhc × 2+2 × 11.9d+4d+4 × Bending adjustment value (blanking)
L (reinforcement length) = [(b-2bhc-d) / 4 × 2+D] × 2+H-2bhc × 2+2 × 11.9d + 8D (budget)
Third:
L (reinforcement length) = [(b-2bhc-d) / 5 + D] × 2+H-2bhc × 2+2 × 11.9d+4d+4 × Bending adjustment value (blanking)
L (reinforcement length) = [(b-2bhc-d) / 5 + D] × 2+H-2bhc × 2+2 × 11.9d + 8D (budget)
Description: 1. D-diameter of longitudinal bar; D -- stirrup diameter; BHC -- protective layer
B-BEAM width; H -- beam height
2. Stirrup hook (135 degrees): 11.9d for seismic, 6.9d for non seismic (grade I reinforcement)
calculation formula of hook length (r = 1.25d):
(1.25 + 0.5) d × one hundred and thirty-five ×(π/ 180) - (1.25 + 1) d + length of straight section (the larger value of anti-seismic is 10d or 75mm, and that of non anti-seismic is 5d)
≈ 1.9d + length of straight section (i.e. 11.9d or 6.9d)
3. Calculation formula of bending adjustment value (90 degrees) (bending radius R is 1.25d):
(1.25 + 0.5) d × ninety ×(π/ 180)-(1.25+0.5)d × 2 ≈ - 0.75D
4. The 135 degree hook of slab member is 6.9d (all as non seismic), and the stirrup hook of bottom slab beam is 11.9d, but the stirrup is not required to be densified (the rest of the bottom slab reinforcement is designed as non seismic)
5. The short reinforcement is laid first, and then the long reinforcement is laid< Four, sump: (omitted)
five, column:
one) concept: according to the different location:
corner column, side column, middle column
the reinforcement in the column is divided by location:
1, bottom layer reinforcement
2, middle layer reinforcement
3 Top layer reinforcement:
(1) beam reinforcement
(2) edge reinforcement
(3) far beam reinforcement
note: beam reinforcement: the reinforcement on the side of the nearest bending beam
to the near rib: bend to the opposite side far away from it
far beam reinforcement: the reinforcement of the beam bending to the far side< Calculation:
1. The number of reinforcement in the column section = 2 × I + J) - 4
i-number of longitudinal load-bearing bars in horizontal row
J-number of longitudinal load-bearing bars in vertical row
2. Foundation layer:
foundation joint bar = thickness of foundation slab - protective layer + length of bars extending into upper layer + bending length a
column Comparison table of anchorage vertical length and hook length of wall joint bar:
anchorage vertical length hook length a
≥ 0.5lae (≥ 0.5la) 12D and ≥ 150
≥ 0.6lae (≥ 0.6la) 10d and ≥ 150
≥ 0.7lae (≥ 0.7la) 8D and ≥ 150
≥ 0.8lae (≥ 0.8la) 6D and ≥ 150
length of foundation and first floor column bar (including first floor and foundation joint bar)= Thickness of foundation slab - protective layer + length of reinforcement extending into upper layer (first layer) + bending length a + height of first layer + length of reinforcement extending into upper layer [see (03g101-1) p42 for length of reinforcement extending into upper layer]
3. Middle layer:
1) column longitudinal reinforcement:
length of longitudinal reinforcement L = storey height - height of this layer extending out of ground + height of upper layer extending out of floor + lap length (if yes) Mechanical connection or welding does not need to add lap length, only add welding shrinkage length adjustment value)
2) stirrup:
stirrup blanking length L = (2H + 2b) - 8bhc + 4D + 4 × Bend adjustment value + 2 × 9 d
effective length of stirrup L = (2H + 2b) - 8bhc + 8D + 2 × 9 d
Description: d-diameter of longitudinal bar; D -- stirrup diameter; BHC -- protective layer
B -- column section width; H -- column section height
★ note: at this time, the bending adjustment value is mostly negative
the blanking and calculation length of the small hoop of the big hoop and small hoop are the same as that of the beam small hoop
number of stirrups = (range length of densified zone / densified spacing) + (range length of non densified zone / non densified spacing) + 1
3) general regulations of densified zone of column:
1 there are three densified zones of column stirrups on the first floor (the first floor here refers to the first floor on the foundation, not necessarily the first floor) ± For the first floor calculated from 0.000, it can also be basement):
a. the length of the stirrup densification area in the lower part is HN / 3
B. the length of the upper stirrup densification zone is Max {500, the dimension of the long side of the column HC, HN / 6}
C. densification within the range of beam joints
note: if the longitudinal reinforcement of the column is bound and lapped, the lapped range shall be increased (the same below)< The length of the upper stirrup densification area is Max {500, the dimension of the long side of the column HC, HN / 6}
B. densification within the range of beam joints
C. the lower part is the same as the upper part
note: if the longitudinal reinforcement of the column is bound and lapped, the lapped range shall be increased (the same below)
HC -- the dimension of the long side of the column; HN the net height of the column< Top column:
the top column is divided into corner column, side column and middle column (middle column)
1) corner column:
longitudinal reinforcement length = floor clear height - reinforcement height of this floor extending out of the ground + anchorage length of top reinforcement (see the following description for the anchorage length of longitudinal reinforcement outside the top column, When welding or mechanical connection)
length of longitudinal reinforcement = clear height of the floor - height of the reinforcement extending out of the ground of the floor + anchorage length of the top reinforcement + binding lap length (the anchorage length of the longitudinal reinforcement outside the top column is shown in the following description. Binding is usually used in budget. If mechanical connection or welding is adopted, the welding or mechanical connection cost is calculated separately according to the agreement of both parties, (excluding lap length)
★ note:
○ 1 internal measurement of reinforcement anchorage length:
A. direct anchor: beam height - protective layer ≥ Lae (LA): beam height - protective layer
B. bending anchor: beam height protective layer < Lae (LA): beam height protective layer + 12D< (2) anchorage length of outer reinforcement:
A. first layer of column top:
A): ≥ 1.5lae (overlapped with longitudinal reinforcement at the upper part of beam)
b): ≥ beam height - protective layer + column width - protective layer + 8D (bending into the inner side of column)
B. the second layer of column top: ≥ beam height - protective layer + column width - protective layer + 8D.
note: the anchorage length of outer reinforcement = max {1.5 Lae, Beam height - protective layer + column width - protective layer}
[see (03g101-1) P37 (seismic) or p43 (non seismic) for details and other instructions
2) side column:
(diagonal column)
3) middle column:
longitudinal reinforcement L = net height of column HN - height of this floor above ground + anchorage length of top layer (if it is lapped, it shall be lapped)
anchorage length value:
○ 1 straight anchor (when beam height protective layer ≥ LAE): beam height protective layer<
2 bending anchor (beam height - protective layer < LAE): beam height - protective layer + 12D.
precautions:
1 when the upper column has more reinforcement than the lower column, the more reinforcement should be inserted into the lower column 1.2lae When the upper column reinforcement is larger than the lower column reinforcement, the upper column reinforcement should extend into the lap joint area of the lower column to lap
3 when the upper column reinforcement is smaller than the lower column reinforcement, the lower column reinforcement should extend into the lap joint area of the upper column to lap
in note 0 2, move the connection position of the lower end up to the upper end of the column (see 03g101-1 p42)
the reinforcement of the lower column more than that of the upper column should extend to 1.2lae (including beam)
(see Figure 1, figure 3 and notes of 03g101-1 p42 for details)
VI. wall:
I) classification of wall:
1
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